Answer:
8 mi = 12.875 km
12.875 /60 m
= 0.21458 km / min
11.7 / 0.21458 = 54.52 min
Using a more concentrated HCl solution and Crushing the CaCO₃ into a fine powder makes the reaction to occur at a faster rate.
<u>Explanation:</u>
CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(aq) + CO₂(g)
When calcium carbonate reacts with hydrochloric acid, it gives out carbon-dioxide in the form of bubbles and there is a formation of calcium chloride in aqueous medium.
The rate of the reaction can be increased by
- Using a more concentrated HCl solution
- Crushing the CaCO₃ into a fine powder
When concentrated acid is used instead of dilute acid then the reaction will occur at a faster rate.
When CaCO₃ is crushed into a fine powder then the surface area will increases thereby increasing the rate of the reaction.
100.0ml*0.400m =xml *2.00m
x=100.0*0.400/2.00= 20 ml 2.0 m CaCl2
you need to take 20 ml 2.0 m CaCl2 and dilute it with water up to 100.0 ml
The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
<h3>
Quantity heat required to convert the ice to liquid</h3>
The total quantity of heat required is calculated as follows;
q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)
q(tot) = mcΔθ₁ + mΔHf + mcΔθ₂
q(tot) = (100)(4.2)(0 - -45) + (334)(100) + (100)(4.2)(75 - 0)
q(tot) = 18,900 J + 33,400 J + 31,500 J
q(tot) = 18.900 kJ + 33.400 kJ + 31.500 kJ
q(tot) = 83,800 J = 83.8 kJ
Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
Learn more about quantity of heat here: brainly.com/question/13439286
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