Answer:
option a) 3 g
Explanation:
mass of Glucose = 5 g
Mass of H₂O = ?
Reaction Given:
6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂
Solution:
First we have to find mass of glucose from balanced reaction.
So,
Look at the reaction
6CO₂ + 6H₂O -------> C₆H₁₂O₆ + 6O₂
6 mol 1 mol
As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )
Convert moles to mass
molar mass of C₆H₁₂O₆ = 6(12) + 12(1) + 6(16)
molar mass of C₆H₁₂O₆ = 72 + 12 + 96
molar mass of C₆H₁₂O₆= 180 g/mol
molar mass of H₂O = 2(1) + 16 = 18 g/mol
Now
6CO₂ + 6H₂O ---------> C₆H₁₂O₆ + 6O₂
6 mol (18 g/mol) 1 mol (180 g/mol)
108 g 180 g
108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)
So
if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).
Apply Unity Formula
108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)
X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)
Do cross multiply
mass of water (H₂O) = 108 g x 5 g / 180 g
mass of water (H₂O) = 3 g
So 3 g of water is required to produce 5 g of glucose.
