Answer:
The force of the radiation on the surface is 3.33 X 10⁻¹⁰ N
Explanation:
Given;
intensity of light, I = 1 kw/m²
area of the surface, A = 1 cm² = 1 x 10⁻⁴ m²
Power of the incident light, P = I x A
Power of the incident light, P = (1 kw/m²) x (1 x 10⁻⁴ m²)
Power of the incident light, P = 1 x 10⁻⁴ kW = 0.1 W
Power of the incident light is given by;
P = Fv
where;
F is the force of the radiation on the surface
v is the speed of light = 3 x 10⁸ m/s
F = P/ v
F = (0.1) / (3 x 10⁸)
F = 3.33 X 10⁻¹⁰ N
Therefore, the force of the radiation on the surface is 3.33 X 10⁻¹⁰ N
