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Oduvanchick [21]
3 years ago
11

Light with an intensity of 1 kW/m2 falls normally on a surface with an area of 1 cm2 and is completely absorbed. The force of th

e radiation on the surface is
Physics
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:

The force of the radiation on the surface is  3.33 X 10⁻¹⁰ N

Explanation:

Given;

intensity of light, I = 1 kw/m²

area of the surface, A = 1 cm² = 1 x 10⁻⁴ m²

Power of the incident light, P = I x A

Power of the incident light, P = (1 kw/m²) x (1 x 10⁻⁴ m²)

Power of the incident light, P = 1 x 10⁻⁴ kW = 0.1 W

Power of the incident light is given by;

P = Fv

where;

F is the force of the radiation on the surface

v is the speed of light = 3 x 10⁸ m/s

F = P/ v

F = (0.1) / (3 x 10⁸)

F = 3.33 X 10⁻¹⁰ N

Therefore, the force of the radiation on the surface is  3.33 X 10⁻¹⁰ N

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Model rocket engines are sized by thrust, thrust duration, and total impulse, among other characteristics. A size C5 model rocke
umka2103 [35]

Answer:

v_{f} = 115.95 m / s

Explanation:

This is an exercise of a variable mass system, let's form a system formed by the masses of the rocket, the mass of the engines and the masses of the injected gases, in this case the system has a constant mass and can be solved using the conservation the amount of movement. Which can be described by the expressions

        Thrust = v_{e}  \frac{dM}{dt}

        v_{f}-v₀ = v_{e} ln ( \frac{M_{o} }{M_{f}} )

where v_{e} is the velocity of the gases relative to the rocket

let's apply these expressions to our case

the initial mass is the mass of the engines plus the mass of the fuel plus the kill of the rocket, let's work the system in SI units

       M₀ = 25.5 +12.7 + 54.5 = 92.7 g = 0.0927 kg

     

The final mass is the mass of the engines + the mass of the rocket

      M_{f} = 25.5 +54.5 = 80 g = 0.080 kg

thrust and duration of ignition are given

       thrust = 5.26 N

       t = 1.90 s

Let's start by calculating the velocity of the gases relative to the rocket, where we assume that the rate of consumption is linear

          thrust = v_{e} \frac{M_{f} - M_{o}  }{t_{f} - t_{o}  }

          v_{e} = thrust  \frac{\Delta t}{\Delta M}

          v_{e} = 5.26 \frac{1.90}{0.080 -0.0927}

          v_{e} = - 786.93 m / s

the negative sign indicates that the direction of the gases is opposite to the direction of the rocket

now we look for the final speed of the rocket, which as part of rest its initial speed is zero

            v_{f}-0 = v_{e} ln ( \frac{M_{o} }{M_{f} } )

we calculate

            v_{f} = 786.93 ln (0.0927 / 0.080)

            v_{f} = 115.95 m / s

5 0
3 years ago
Question 2 (10 points)
kenny6666 [7]

The force required to slow the truck was -5020 N

Explanation:

First of all, we find the acceleration of the truck, which is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

For the truck in this problem,

v = 11.5 m/s

u = 21.9 m/s

t = 2.88 s

So the acceleration is

a=\frac{11.5-21.9}{2.88}=-3.6 m/s^2

where the negative sign means that this is a deceleration.

Now we can find the force exerted on the truck, which is given by Newton's second law:

F=ma

where

m = 1390 kg is the mass of the truck

a=-3.6 m/s^2 is the acceleration

And substituting,

F=(1390)(-3.6)=-5004 N

So the closest answer among the option is -5020 N.

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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because they are both working together

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The chart shows the power ratings of 3 clothes dryers and the time needed to dry a load of 10 towels.
atroni [7]

Answer:

12010

Explanation:

Given:

power    time

4,370     25

4,420     22

4,150      26

To find: difference in energy used between the dryer that uses the greatest amount of energy and the dryer that uses the least amount

Solution:

Energy = power × time

For clothes dryer x:

energy = 4370 × 25 = 109250

For clothes dryer y:

energy = 4420 × 22 = 97240

For clothes dryer z:

energy = 4150 × 26 = 107900

Dryer x uses the greatest amount of energy and dryer y uses the least amount of energy.

Difference in energy used between the dryer that uses the greatest amount of energy and the dryer that uses the least amount = 109250 - 97240 = 12010

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