Answer:
Since the equation is a quadractic, the graph would be a parabola.
With a being -1, the parabola will represent a reflection of the y values. In other words, the parabola will be upside down and the vertex will be a maximum value. Ultimately, the <em>a </em>in the function doesn't determine the location of the vertex.
Since the k value is negative, that means the equation begins <em>y - (-k)</em>. The K value being negative restricts the transformation of the parabola to being down <em>k</em> number of units. The location of moving the parabola down places the vertex in the third or fourth quadrant.
The <em>h</em> value being positive means that the parabola is shifted to the right <em>h</em> number of units. For example, if the parabola <em>f(x) = x² </em>has a vertex at (0,0), the parabola <em>f(x) = (x-2)²</em> must have a vertex at (2,0) because 2 - 2 = 0. Shifting right places the vertex of the parabola in the first or fourth quadrant.
Therefore the k value and h value restrictions must overlap in the fourth quadrant.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
The domain is the x-values. So domain is 3. Range is y-values. So range is -2, 1, 4,7, and 8. When writing either range or domain don't repeat numbers ,(example: domain is 3,3,3: wrong) and try putting the numbers from least to greatest.
Answer:
no
Step-by-step explanation:
I’m not sure but something is telling me that is D
