Answer : The de Broglie wavelength will be 
Solution :
The formula used for de Broglie wavelength is:
..........(1)
where,
= wavelength = ?
h = Planck's constant = 
m = mass = 1.2 g = 0.0012 kg
Conversion used : 1 kg = 1000 g
v = velocity = 150 m/s
Now put all the given values in equation 1, we get:


Therefore, the de Broglie wavelength will be 
Answer:
430 kPa
Explanation:
Use the formula PV/T = PV/T where the left side of the equation refers to the initial values and the right side refers to the final values: (170.2 kPa)(3.5 L)/(298 K) = (P)(1.35 L)/(293 K). The P represents the unknown pressure. Solving this equation gives us a value for P of 433.855 kPa, but because of significant figures (the two from 3.5 L), we round to 430 kPa.
A. 6 moles
B. 9 moles
C. 3 moles
D. 20 moles
I think please check me, in case I am wrong
Answer:
B is sedimentary and A is metermorphic