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3 years ago

10

Why is the gravitational potential energy of an object 1 meter above the moon’s surface less than its potential energy 1 meter a

bove Earth’s surface?
A. The object’s mass is less on the moon.
B. The object’s weight is more on the moon.
C. The object’s acceleration due to gravity is less on the moon.
D. both a and c

1 answer:

dsp733 years ago

3 0

Potential energy relative to the surface is

(mass) x (<span>acceleration due to gravity) x (height above the surface).

At 1.0 meter above the surface, that is

</span> (mass) x (<span>acceleration due to gravity) x (1.0 meter) .

The object's mass doesn't change, so the only thing that has any effect
on its potential energy at 1 meter above the surface is the acceleration
of gravity or, in other words, the surface of <em><u>what</u></em> ?

</span>

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Answer with Explanation:

We are given that

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3 years ago

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3 years ago

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a) In the attachment we can see a diagram of the forces in this problem and the coordinate axes for its decomposition.

F is the force applied by the spring, while it is compressed, this force disappears when the block leaves the spring

b) Let's apply Newton's second law for when the spring is compressed

let's use trigonometry to break down the weight

sin θ = Wₓ / W

cos θ = W_y / W

Wₓ = W sin θ

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N = W cos θ

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F = k Δx

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d) In this part they give the angle θ = 45º and there is no friction, they ask the compression

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3 years ago