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Fudgin [204]
3 years ago
10

Why is the gravitational potential energy of an object 1 meter above the moon’s surface less than its potential energy 1 meter a

bove Earth’s surface?
A. The object’s mass is less on the moon.
B. The object’s weight is more on the moon.
C. The object’s acceleration due to gravity is less on the moon.
D. both a and c
Physics
1 answer:
dsp733 years ago
3 0

Potential energy relative to the surface is

         (mass) x (<span>acceleration due to gravity) x (height above the surface).

At 1.0 meter above the surface, that is

</span>          (mass) x (<span>acceleration due to gravity) x (1.0 meter) .

The object's mass doesn't change, so the only thing that has any effect
on its potential energy at 1 meter above the surface is the acceleration
of gravity or, in other words, the surface of <em><u>what</u></em> ?

</span>
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"Two rooms are connected by a doorway. You are in one room and your friend is in the other room. Explain why you can hear your f
Masteriza [31]

Answer:

You can  hear your friend because of diffraction of sound waves.

Explanation:

Through diffraction of sound waves, the sound waves can bend around the door spaces and spread out through any small opening on the door to reach you in the other room yet the other person is not in a direct line with you.The wavelength of sound waves in this case are longer enough to bend around the obstacle(door and the indirect path) and spread out to reach your room for you to hear your friend without directly being in line with the door for you to see them.

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5 0
3 years ago
A partition divides an insulated tank into two parts. One part of the tank contains 2.5 kg of compressed liquid water at 60°C an
jeka94

Answer:

V=0.972m^2

Explanation:

the energy balance is :

E_{in} -E_{out} =ΔE_{system}

0=ΔU=mm(u_{2} -u_1)

u_1=u_2

the properties of water are from table

P_1=500 kpa\\T_1=60 degree C\\v_1=v_f_{-->60} =251.6 Kj/Kg

verified if we get a quantity between 0 and 1

P_2=10 kpa\\u_2=u_1

we have,

v_f=0.001\\v=14.670 m^3/kg\\u_f=191.79\\v_{fg}=2245.4 Kj/Kg\\

therefore,

x_2=\frac{u_2-u_f}{u_{fg} }

we replace the values in this equation:

x_2=\frac{251.6-191.79}{2245.4}\\ x_2=0.026

so,

T_2=T_{sat--10kpa} =45.81\\v_2=v_f-x_2v_{fg}

we replace the values in this equation:

v_2=0.38886m^3/kg

we have,

V=mv_2

we replace the values in this equation:

V=0.972m^2

6 0
3 years ago
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