Ask question

Ask question

All categories

2 years ago

11

Alyssa is taking a walk on a nature path near her neighborhood. She

1 answer:

Montano1993 [528]2 years ago

4 0

Answer:

C. Sources of electrical current!

Hope this helps :)

You might be interested in

What is the function of the bronchioles?<br> please help

beks73 [17]

Answer:

The bronchioles function is to deliver air to tiny sacs called alveoli where oxygen and carbon dioxide are exchanged.

Explanation:

Bronchioles are air passages inside the lungs that branch off like tree limbs from the bronchi—the two main air passages into which air flows from the trachea (windpipe) after being inhaled through the nose or mouth. The bronchioles deliver air to tiny sacs called alveoli where oxygen and carbon dioxide are exchanged.

4 0

2 years ago

Which of the following examples illustrates static friction?

vivado [14]

Answer:

A box sits stationary on a ramp

Explanation:

Static friction is a force which keeps an object at rest as it is in the case of the box. It has to be overcome for the object to be set into motion.

Static force of friction is calculated as follows:

F= μη

F is static force of friction.

μ is the coefficient of static friction.

η is the normal force.

6 0

3 years ago

What do refrigerators and air conditioners use to move heat?

Aleksandr [31]

your answer is Freon

3 0

3 years ago

Read 2 more answers

A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the

svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength is given by

$\lambda = \dfrac{2L}{n}$

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

$f = n\dfrac{v}{2L}$

now, wavelength calculation

n = 1

$\lambda_1 = \dfrac{2\times 2}{1}$

λ₁ = 4 m

n = 2

$\lambda_2 = \dfrac{2\times 2}{2}$

λ₂ = 2 m

n =3

$\lambda_3 = \dfrac{2\times 2}{3}$

λ₃ = 1.333 m

now, frequency calculation

n = 1

$f = n\dfrac{v}{2L}$

$f_1 =1\times \dfrac{50}{2\times 2}$

f₁ = 12.5 Hz

n = 2

$f = n\dfrac{v}{2L}$

$f_2 =2\times \dfrac{50}{2\times 2}$

f₂= 25 Hz

n = 3

$f = n\dfrac{v}{2L}$

$f_3 =3\times \dfrac{50}{2\times 2}$

f₃ = 37.5 Hz

8 0

3 years ago

A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done

Alexxandr [17]

Force=150N
Angle=60°
Displacement=50m

$\boxed{\sf W=Fscos\Theta}$

$\\ \sf\longmapsto W=150(50)cos 60$

$\\ \sf\longmapsto W=7500\times \dfrac{1}{2}$

$\\ \sf\longmapsto W=3750J$

6 0

2 years ago