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3 years ago

The natural force that causes you to lose power as you climb a hill is known as inertia.

Physics

2 answers:

Juliette [100K]3 years ago

7 0

Yeah your answer is correct

iren2701 [21]3 years ago

4 0

Answer:

FALSE

Explanation:

When we climb up on the hill then in that case we need to do work against the force of gravity.

Here we know that our body is attracted towards the center of Earth due to the force of gravity. When we climb up the hill then we have to work against the gravity.

So here work done to climb up the hill of height "h" is given as

$W = mgh$

now we know that while moving up the work done by us is against the gravitational force so this is the energy consumed or loss of energy.

hence the natural force against which we are losing our power is gravitational force.

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A small but measurable current of 5.8 × 10-10 A exists in a copper wire whose diameter is 3.0 mm. The number of charge carriers

swat32

Answer:

a) The current density ,J = 2.05×10^-5

b) The drift velocity Vd= 1.51×10^-15

Explanation:

The equation for the current density and drift velocity is given by:

J = i/A = (ne)×Vd

Where i= current

A = Are

Vd = drift velocity

e = charge ,q= 1.602 ×10^-19C

n = volume

Given: i = 5.8×10^-10A

Raduis,r = 3mm= 3.0×10^-3m

n = 8.49×10^28m^3

a) Current density, J =( 5.8×10^-10)/[3.142(3.0×10^-3)^2]

J = (5.8×10^-10) /(2.83×10^-5)

J = 2.05 ×10^-5

b) Drift velocity, Vd = J/ (ne)

Vd = (2.05×10^-5)/ (8.49×10^28)(1.602×10^-19)

Vd = (2.05×10^-5)/(1.36 ×10^10)

Vd = 1.51× 10^-5

8 0

3 years ago

Read 2 more answers

An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance f

EleoNora [17]

Answer:

364days

Explanation:

Pls see attached file

Explanation:

8 0

3 years ago

) A stone initially moving at 8.0 m/s on a level surface comes to rest due to friction after it travels 11 m. What is the coeffi

natali 33 [55]

Answer:

-0.3

Explanation:

F' = μmg ........... Equation 1

Where F' = Frictional force, μ = coefficient of kinetic friction, m = mass of the stone, g = acceleration due to gravity.

But,

F' = ma ............ Equation 2

Where a = acceleration of the stone.

Substitute equation 2 into equation 1

ma = μmg

dividing both side of the equation by m

a = μg

make μ the subject of the equation

μ = a/g............... Equation 3

From the equation of motion,

v² = u²+2as................. Equation 4

Where v and u are the final and the initial velocity respectively, s = distance.

Given: v = 0 m/s (to rest), u = 8.0 m/s, s = 11 m.

Substitute into equation 4

0² = 8² + 2×11×a

22a = -64

a = -64/22

a = -32/11 m/s² = -2.91 m/s²

substitute the values of a and g into equation 3

μ = -2.91/9.8

μ = -0.297

μ ≈ -0.3

4 0

3 years ago

A bike travels at a constant speed for 4.00 m/s for 5.00 seconds. How far does it go

kicyunya [14]

Answer:

20 metres

Explanation:

Speed = distance ÷ time

$s = \frac{d}{t}$

If we substitute the values:

$4 = \frac{d}{5}$

$20 = d$

3 0

3 years ago

Read 2 more answers

A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coord

Murljashka [212]

Answer:

center of mass = −0.50 m

Explanation:

given data

mass m1 = 3.04 kg

distance xm = -8 m

mass m2 = 5.61 kg

distance xM = 3.56 m

solution

we get here center of mass for n mass of system that is express as

center of mass = $\frac{m_1x_1+m_2x_2......m_nx_n}{m_1+m_2...m_n}$ ......................1

but we have only 2 particle system so we will get

center of mass = $\frac{m1 \times xm+m2 \times xM}{m1+m2}$ .................2

put here value and we will get

center of mass = $\frac{3.04 \times (-8 )+5.61 \times 3.56}{3.04 + 5.61}$

solve it we will get

center of mass = −0.50 m

8 0

3 years ago