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2 years ago

5) What type of substance can seep groundwater and make it unusable?

Physics

1 answer:

sergeinik [125]2 years ago

7 0

Answer:

I believe chemicals, though I might be wrong.

Explanation:

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Easy Plz Help Physics

Serhud [2]

Answer:

is it conduction because in that case it would be

Explanation:

the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.

4 0

3 years ago

What demonstrates conduction

Anastaziya [24]

Heating a pot of water on a stove top or benson burner. The water is heated through direct contact.

5 0

3 years ago

Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°C 50C water. (C = .5 for ice, C 1 for water,

Nitella [24]

Answer: The amount of heat needed is 29000 Cal.

Explanation:

The process involved in this problem are:

$(1):H_2O(s)(-30^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(50^oC)$

Now, we calculate the amount of heat released or absorbed in all the processes.

For process 1:

$q_1=mC_{p,s}\times (T_2-T_1)$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of ice = 200 g

$T_2$ = final temperature = $0^oC$

$T_1$ = initial temperature = $-30^oC$

Putting all the values in above equation, we get:

$q_1=200g\times 0.5Cal/g^oC\times (0-(-30))^oC=3000Cal$

For process 2:

$q_2=m\times L_f$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 200 g

$L_f$ = latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

$q_2=200g\times 80Cal/g=16000Cal$

For process 3:

$q_3=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

$q_3$ = amount of heat absorbed = ?

m = mass of water = 200 g

$T_2$ = final temperature = $50^oC$

$T_1$ = initial temperature = $0^oC$

Putting all the values in above equation, we get:

$q_3=200g\times 1Cal/g^oC\times (50-0)^oC=10000Cal$

Calculating the total heat absorbed, we get:

$Q=q_1+q_2+q_3$

$Q=3000+16000+10000=29000Cal$

Hence, the amount of heat needed is 29000 Cal.

7 0

3 years ago

A boy of mass 50 kg exerts a pressure of 25000 pa calculate the area

gtnhenbr [62]

Answer: A = 0.02 m²

Explanation: Solution:

Pressure is expressed in the formula:

P = F / A where F = mg

= mg /A

= 50 kg ( 9.8 m/s²) / 25000 Pa

= 0.02 m²

3 0

3 years ago

Two protons are moving up when they enter a magnetic field that points towards you. What happens to the motion of the particles?

Llana [10]

The protons will possess a force pointing to the right.

The force is called Laurentz Force, which is measured by: F = qvB

Here, q is positive for proton, v and B are cross product determined by right hand rule.

6 0

3 years ago

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