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3 years ago

Circle the larger unit:

Physics

1 answer:

DerKrebs [107]3 years ago

4 0

1. Centimeter
2. Kilogram
3. Millisecond
4. DL
5. Kg
6. Mm
7. S
8. Mm
9. Us

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The electric field strength between the plates of a simple air capacitor is equal to the voltage across the plates divided by th

Dmitry [639]

Answer:

d = V/E

Explanation:

From the definition, we can say that the electric field strength between the plates of a parallel plate capacitor is

E = v/d

where

E = electric field strength

V = potential difference

d = distance between the plates

On rearranging the equation and making d subject of the formula, we have

d = V/E

From the question, we're given that

V = 112 V

E = 1.12 kV/cm converting to V/m, we have 110000 V/cm

d = 112 / 110000

d = 0.00102 m

d = 1.02*10^-3 m

5 0

3 years ago

How many full length strands of hair are collected from the scalp to use as a sample?

laila [671]

50 strands is the standard procedure

4 0

3 years ago

A wheel of radius R, mass M, and moment of inertia I is mounted on a frictionless, horizontal axles. A light cord wrapped around

Alex_Xolod [135]

Answer:

$\alpha =\frac{m*g*R}{I-m*R^2}$

$a = \frac{m*g*R^2}{I-m*R^2}$

$T=\frac{I*m*g}{I-m*R^2}$

Explanation:

By analyzing the torque on the wheel we get:

$T*R=I*\alpha$ Solving for T: $T=I/R*\alpha$

On the object:

$T-m*g = -m*a$ Replacing our previous value for T:

$I/R*\alpha-m*g = -m*a$

The relation between angular and linear acceleration is:

$a=\alpha*R$

So,

$I/R*\alpha-m*g = -m*\alpha*R$

Solving for α:

$\alpha =\frac{R*m*g}{I+m*R^2}$

The linear acceleration will be:

$a =\frac{R^2*m*g}{I+m*R^2}$

And finally, the tension will be:

$T =\frac{I*m*g}{I+m*R^2}$

These are the values of all the variables: α, a, T

8 0

3 years ago

A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless trac

liraira [26]

Answer:

2.7 s

Explanation:

The period of the motion of a massless loaded spring is given by

$T = 2\pi\sqrt{\dfrac{m}{k}}$

where m is the mass of the load and k is the force or spring constant.

Using values in the question and converting to appropriate units,

$T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}$

5 0

3 years ago

Read 2 more answers

The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?

Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

$b=6-4 = 2$

And height:

$h=4-0 = 4$

Therefore, the area is

$A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4$

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0

3 years ago