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2 years ago

Circle the larger unit:

Physics

1 answer:

DerKrebs [107]2 years ago

4 0

1. Centimeter
2. Kilogram
3. Millisecond
4. DL
5. Kg
6. Mm
7. S
8. Mm
9. Us

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If the magnitude of a charge is half as much as another charge, but the force experienced is the same, then the electric field s

Kazeer [188]

Answer:

the electric field strength of this charge is two times the strength of the other charge

Explanation:

Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;

E1/E2 = Q2/Q1

E2 = E1 x Q1/Q2

= E x Q/ (Q/2)

= 2E

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2 years ago

Why are nuclear power plants controversial

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Because a nuclear meltdown can be caused if systems fail.

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2 years ago

1 kg air in a piston-cylinder assembly is heated at constant pressure, resulting the expansion of the volume. the initial temper

rewona [7]

Answer:

57,42 KJ

Explanation:

By a isobaric proces, the expresion for the works in the jpg adjunt. Then:

W = Pa(Vb - Va) = Pa*Vb - Pa*Va ---(1)

By the ideal gases law: PV=RTn

Then, in (1): (remember Pa = Pb)

W = R*Tb*n - R*T*an = R*n*(Tb - Ta) --- (2)

Since we have 1 Kg air: How much is this in moles?

From bibliography: 28.96 g/mol

Then, in 1 Kg (1000 g) there are:

n = 34,53 mol

Finally, in (2):

W = (8,3144 J/K.mol)*(34,53 mol)*(500K - 300K) = 51 419,9 J ≈ 57,42 KJ

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3 years ago

The product side of a chemical reaction is shown. → 7Ti2(SO4)3

Alex_Xolod [135]

The answer is the fourth choice because there are 7 represents in a coefficient.

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3 years ago

Read 2 more answers

A crew on a spacecraft watches a movie that is two hours long. The spacecraft is moving at high speed through space. An Earth-ba

laiz [17]

Answer:

The duration of the movie is longer than 2 hrs.

Explanation:

Given:

The duration of the movie observed by the crew on the spacecraft is 2 hrs.

According to time-dilation formula:

$t = \dfrac{t_{0}}{\sqrt{1 - \dfrac{v^{2}}{c^{2}}}}$

Here, $t$ is the required time, $t_{0}$ is the original time, $v$ is the velocity of the spacecraft and $c$ is the velocity of light.

Since $v$ , so $t_{0} > t$ .

So the time required will be large.

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3 years ago