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Stells [14]
3 years ago
7

Elizabeth notices that the temperature is dropping. What piece of lab equipment should she use to measure the change in temperat

ure?
A) hand lens
B) thermometer
C) spring scale
D) graduated cylinder
Physics
2 answers:
Sergeu [11.5K]3 years ago
8 0
Thermometer because that’s an equipment you would use to find out the temperature
bixtya [17]3 years ago
4 0

Answer:

thermometer

Explanation:

the thermometer measures temp.

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andriy [413]

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They are temperature, atmospheric pressure, wind, humidity, precipitation, and cloudiness. Together, these components describe the weather at any given time.

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3 years ago
SOMEONE HELP ME PLEASE!!!!!
enyata [817]

Answer:

I think it would be the 3rd or 4th one.

8 0
3 years ago
A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7
maxonik [38]
First, let's find the speed v_i of the two blocks m1 and m2 sticked together after the collision.
We can use the conservation of momentum to solve this part. Initially, block 2 is stationary, so only block 1 has momentum different from zero, and it is:
p_i = m_1 v_1
After the collision, the two blocks stick together and so now they have mass m_1 +m_2 and they are moving with speed v_i:
p_f = (m_1 + m_2)v_i
For conservation of momentum
p_i=p_f
So we can write
m_1 v_1 = (m_1 +m_2)v_i
From which we find
v_i =  \frac{m_1 v_1}{m_1+m_2}= \frac{(3.5 kg)(6.3 m/s)}{3.5 kg+1.7 kg}=4.2 m/s

The two blocks enter the rough path with this velocity, then they are decelerated because of the frictional force \mu (m_1+m_2)g. The work done by the frictional force to stop the two blocks is
\mu (m_1+m_2)g  d
where d is the distance covered by the two blocks before stopping.
The initial kinetic energy of the two blocks together, just before entering the rough path, is
\frac{1}{2} (m_1+m_2)v_i^2
When the two blocks stop, all this kinetic energy is lost, because their velocity becomes zero; for the work-energy theorem, the loss in kinetic energy must be equal to the work done by the frictional force:
\frac{1}{2} (m_1+m_2)v_i^2 =\mu (m_1+m_2)g  d
From which we can find the value of the coefficient of kinetic friction:
\mu =  \frac{v_i^2}{2gd}= \frac{(4.2 m/s)^2}{2(9.81 m/s^2)(1.85 m)}=0.49
3 0
3 years ago
Does heating a cup of<br> Water allow it to dissolve more sugar ? Constant
Anestetic [448]

Answer:

Explanation:

Yes

5 0
3 years ago
Read 2 more answers
What is the difference between a distance time graph and a speed time graph?
Feliz [49]

Answer:

speed-time graph is the acceleration of the particle or straight lines acceleration is constant

a distance-time graph represents that a particle has constant speed.

Explanation:

3 0
3 years ago
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