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Molodets [167]
3 years ago
8

What happens when multiple forces act upon an object?

Physics
2 answers:
levacccp [35]3 years ago
8 0
They all combine to affect the object as if there were one single force. It's not hard to calculate the strength and direction of that one equivalent force. It can turn out to be zero. Then the group of several forces is said to be 'balanced'.
Bogdan [553]3 years ago
7 0
The object will move if the forces are unbalanced.

Newtons second tells you that when a net force (the unbalanced force) is applied to and object it will produce an acceleration (movement) in direct proportion to the force and in inverse proportion to the mass of the object. 
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Please someone help me.
katovenus [111]

Answer:

acceleration of the car is 3 m\s^2

Explanation:

from rest means the initial velocity (vi) is zero

time = 5s

final velocity (vf) = 15m\s

a = vf - vi \ t

a = (15-0) \ 5

a= 3 m\s^2

which means that the car is speeding up 3 meters every second

5 0
4 years ago
How will the electrostatic force between two electric charges change if the first charge is doubled and the second charge is onl
Vinvika [58]

Answer:

B) \frac{2}{3}

Explanation:

The electric force between charges can be determined by;

F = \frac{kq_{1} q_{2} }{r^{2} }

Where: F is the force, k is the Coulomb's constant, q_{1} is the value of the first charge, q_{2} is the value of the second charge, r is the distance between the centers of the charges.

Let the original charge be represented by q, so that;

q_{1} = 2q

q_{2} = \frac{q}{3}

So that,

F = q_{1}q_{2} x \frac{k}{r^{2} }

  = 2q x \frac{q}{3} x \frac{k}{r^{2} }

  = \frac{2q^{2} }{3} x \frac{k}{r^{2} }

  = \frac{2}{3} x \frac{kq}{r^{2} }

F = \frac{2}{3} x \frac{kq}{r^{2} }

The electric force between the given charges would change by \frac{2}{3}.

4 0
3 years ago
Consider two planets of mass m and 2m,
Rzqust [24]

Answer:

Part a)

\frac{F_1}{F_2} = 10.125

Part b)

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

\frac{T_1}{T_2} = 9.54

Explanation:

Part a)

As we know that the gravitational force is given as

F = \frac{GMm}{r^2}

so we will have to find the ratio of force on two planets due to star

so here we have

\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}

\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}

\frac{F_1}{F_2} = 10.125

Part b)

Orbital speed is given as

v = \sqrt{\frac{GM}{r}}

so the ratio of two orbital speed is given as

\frac{v_1}{v_2} = \frac{r_2}{r_1}

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

Time period is given as

T = 2\pi\sqrt{\frac{r^3}{GM}}

so the ratio of two time period is given as

\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}

\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}

\frac{T_1}{T_2} = 9.54

8 0
3 years ago
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Velocity is speed in a given<br><br> • space<br> • direction <br> • number <br> • problem
Mariana [72]
Direction direction direction
4 0
3 years ago
In ice cap climates, the intense cold _____.
crimeas [40]

Answer:

A. is true

Explanation:

3 0
3 years ago
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