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Elanso [62]
3 years ago
13

WILL MARK BRAINLIEST

Chemistry
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

8.28 × 10⁶ N

Explanation:

Step 1: Given data

Interior surface area of the habitat (S): 110 m²

Pressure in the habitat (P): 75.3 kPa

Step 2: Convert "P" to Pascal

We will use the conversion factor 1 kPa = 10³ Pa.

75.3 kPa × (10³ Pa/1 kPa) = 75.3 × 10³ Pa

Step 3: Calculate the total force exerted (F)

We will use the following expression.

P = F/S

F = P × S

F = 75.3 × 10³ Pa × 110 m²

F = 8.28 × 10⁶ N

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Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and character
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Answer:

Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)

2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)

Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)

Explanation:

We're given the following ions:

Fe^{2+}, Cr^{3+}, Ni^{2+}

Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.

Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:

Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)

Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:

2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)

Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide:

Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)

7 0
3 years ago
A 15.0 L tank of gas contained at a high pressure of 8.20 • 10^4 torr. The tank is opened and the gas expands into an empty cham
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Answer:

P₂ = 0.205torr

Explanation:

Boyle's law relates the pressure and volume of a gas under two different conditions. The equation is:

P₁V₁ = P₂V₂

<em>Where P is pressure and V volume of of 1, initial conditions and 2, final conditions.</em>

P₂ is our incognite

Replacing:

P₁V₁ = P₂V₂

8.20x10⁴torr*15.0L = P₂*600x10⁴L

<h3>P₂ = 0.205torr</h3>

<em />

4 0
3 years ago
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Answer:

.

Explanation:

4 0
3 years ago
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For a concentration technique, Stotal is given as 19.31 ± 0.035, Smb is 0.22 ± 0.008, and kA is 0.154 ± 0.007 ppm–1, where Stota
professor190 [17]

Answer:

B

Explanation:

8 0
3 years ago
Match each type of titration to its ph at the equivalence point for solutions at 25 ∘c. drag each item to the appropriate bin. v
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The complete question;
Match each type of titration to its pH at the equivalence point.
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Strong acid, strong base
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pH less than 7
pH equal to 7
<span>pH greater than 7
</span>Answer:
weak acid, strong base - pH greater than 7
Strong acid, strong base - pH equal to 7
Weak base, strong acid - pH less than 7
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Strong bases dissociate completely to give out OH⁻ ions.
When strong acids and strong bases are mixed the dissociated H⁺ and OH⁻ ions  react and neutralise each other, making the solution neutral.
Weak acids cannot completely dissociate, only a fraction of H⁺ ions are dissociated. Same applies for weak bases.
When weak acid and strong base is mixed, whilst the strong acid completely dissociates, weak base only partially dissociates. Therefore the amount of H⁺ ions is greater than OH⁻ ions, overall pH is more acidic, hence less than 7.
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5 0
3 years ago
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