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Ann [662]
4 years ago
13

A spacecraft is flying toward the moon. The moonÍs gravitational pull on the spacecraft will ___________.

Physics
2 answers:
kifflom [539]4 years ago
4 0
A. Increase is correct because the statement said the moons gravitational "PULL"
Veseljchak [2.6K]4 years ago
4 0

<span>The correct answer between all the choices given is the first choice or letter A, which is increase. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

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Find the density of an object that has a mass of 5 kg and a volume of 50 cm3
serg [7]
Density = mass/volume. 5000/50= 100 grams per cubic centimeter. No substance on Earth has anywhere near that density. Tops is about 20 for osmium and gold.
3 0
4 years ago
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Two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4
Fofino [41]

Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.

<h3>What is Coulomb's law?</h3>

Coulomb's law can be expressed as that the electrical force between two charged bodies is directly proportional to the product of the quantity of charge on the bodies and inversely proportional to the square of the separation distance between the two bodies.

As given in the problem two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of - 8.9•10-4 C.

As per coulomb's law, opposite charges attract each other.

Thus, If one sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.

Learn more about Coulomb's law here ;

brainly.com/question/506926

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5 0
1 year ago
Which of the following are true about S waves
shusha [124]

Answer:

3. they can travel through solids

4. they move rock at right angles to the direction of wave travel

Explanation:

  • S waves are called transverse waves they have the ability to move past the solids. They cannot move through the liquids, these waves are perpendicular to the direction of travel.  
  • They are also called longitudinal waves, the ad is second to record on the seismograph as they slowly pass through the rocks. They have a speed of 3.4 to 7.2 km as per the boundary.
6 0
3 years ago
Now Abel and Kato use what they learned to answer the following problem. The initial speed of a tennis ball is 54 m/s and the la
34kurt

Answer:

h=19.4m

R=199.07 m

Explanation:

To solve this problem we use the parabolic motion equations:

We define:

v_{i}total initial speed  =54\frac{m}{s}

\alpha=angle that forms the total initial speed with the horizontal line= 21°

v_{ix}:initial speed component in horizontal direction

=v_{i} cos\alpha =54*cos 21= 50.41 m/s

v_{iy}:initial speed component in vertical direction

=v_{i} sin\alpha=54*sin21=19.35 m/s

v_{x} :horizontal speed at any point on the parabolic path

v_{y}: vertical speed at any point on the parabolic path

g= acceleration of gravity= 9,8\frac{m}{s^{2} }  

Equation of the speed of the football in the vertical direction :

(v_{y} )^{2} =(v_{yi} )^{2} -2*g*y  Equation (1)

Calculation of the maximum height(h)

The speed of the ball (vy) in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.

We replace y=h, v_{y} =0,  v_{iy} = 19.39\frac{m}{s}, g=9.8\frac{m}{s^{2} } in the equation(1)

0=19.35^{2} -2*9.8*h

h=\frac{19.35^{2} }{2*9.8}

h=19.1 m

Calculating of the range (R)

Fórmula: R=v_{ix} *t   (m)   Equation (2)

R is the maximum horizontal distance the ball reaches.

The time (t) for the ball to reach R is twice the time the ball spends to reach the maximum height. Then, we calculate the time(t_{h} )) when the ball reaches the maximum height

We apply the following equation to calculate t_{h}:

v_{y} =v_{iy} -g*t_{h}

0=19.35-9.8*t_{h}

9.8*t_{h} =19.35

t_{h} =\frac{19.35}{9.8}

t_{h} =1.97 s

t=2*t_{h}

t=3.95 s  

We replace v_{ix} =50.41 \frac{m}{s} and t=3.95\frac{m}{s} in the equation (2)

R=50.41*3.95

R=199.07 m

6 0
3 years ago
Give an example of how friction can be used and an example of how friction can be harmful
DaniilM [7]

Answer:

friction can be used to slow things down but it can also be harmful because it can cause fire to start

5 0
4 years ago
Read 2 more answers
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