Answer:
D. will decrease slightly in volume when heated to 6° C
Explanation:
By Bernoulli Theorem, We know, that for any two points in the pipe, total energy would be same.
Pressure Energy + K.E. of 1st pipe = Pressure Energy + K.E. of 2nd pipe
[ No need to consider Potential energy as height isn't mentioned]
P₁ + mv₁²/2 = P₂ + mv₂²/2
So, we know, P + mv²/2 = constant
As value of kinetic energy is larger in larger in 2 in. pipe [ 'cause area is indirectly proportional to velocity ], Value of pressure energy would be smaller in it. So, pressure energy will be higher in the pipe of 3 in.
In short, option A would be your correct answer.
Hope this helps!
Answer:
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Explanation:
Total force required = Mass x Acceleration,
F = ma
Here we need to consider the system as combine, total mass need to be considered.
Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg
We need to accelerate the group of rocks from the road at 0.250 m/s²
That is acceleration, a = 0.250 m/s²
Force required, F = ma = 1744 x 0.25 = 436 N
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.
where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
![240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]](https://tex.z-dn.net/?f=240%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A%28%5Cfrac%7B1h%7D%7B3600s%7D%20%29%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D66.67%5Bm%2Fs%5D)
Now replacing:
![66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]](https://tex.z-dn.net/?f=66.67%20%3D%200%20%2Ba%2A2%5C%5Ca%20%3D%2033.33%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a
![925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]](https://tex.z-dn.net/?f=925000%3Dm%2A33.33%5C%5Cm%20%3D%20925000%2F33.33%5C%5Cm%20%3D%2027752.7%20%5Bkg%5D)
