P=I^2 *R
600 =5.0^2 *R
R=24
Answer: 24 ohms
I hope it’s correcttttttt...
Answer:
The acceleration of the car, a = -3.75 m/s²
Explanation:
Given data,
The initial velocity of the airplane, u = 75 m/s
The final velocity of the plane, v = 0 m/s
The time period of motion, t = 20 s
Using the I equations of motion
v = u + at
a = (v - u) / t
= (0 - 75) / 20
= -3.75 m/s²
The negative sign indicates that the plane is decelerating
Hence, the acceleration of the car, a = -3.75 m/s²
Answer:
The neutron is a subatomic particle, symbol
n
or
n0
, with no electric charge and a mass slightly greater than that of a proton. Protons and neutrons constitute the nuclei of atoms. Since protons and neutrons behave similarly within the nucleus, and each has a mass of approximately one atomic mass unit, they are both referred to as nucleons.[6] Their properties and interactions are described by nuclear physics.
Explanation:
pls mark me as BRAINLIEST
Vb - Va = -366.7 V.
Vab = Va - Vb, the potential of a with respect to b, is equal to the work done by the electric force when a unit of charge moves from a to b, it is given by:
Vab = Va - Vb = Wab/q,
So, in order to determinate the potential difference Vb - Va we have to multiply by -1 both side of the equation above:
- (Va - Vb) = - (Wab/q)
Resulting
Vb - Va = -(Wab/q)
Given a positive charge q = 6.0μC = 6.0x10⁻⁶C, Wab = 2.2x10⁻³J. Determine Vb - Va.
Vb - Va = - (2.2x10⁻³J/6.0x10⁻⁶C)
Vb - Va = -366.7 J/C = -366.7 V
