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Ber [7]
2 years ago
9

An important natural and metallic resource is ?

Chemistry
2 answers:
erastovalidia [21]2 years ago
8 0

The answer is D, Platinum. Hope this helps.

ss7ja [257]2 years ago
3 0
The answer is B.) Carbon
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Which is a plausible explanation of why some plants, such as the Japanese red maple, are not green in color?
nika2105 [10]
I would have to say c if I am wrong sorry:)
4 0
3 years ago
Read 2 more answers
What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?
Maru [420]

When sodium amide i.e.NaNH_{2} reacts with water i.e. H_{2}O results in the formation of sodium hydroxide i.e. NaOH and ammonia NH_{3}.

The chemical reaction is given by:

NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH

Now, when ammonia i.e.NH_{3} reacts with water results in the formation of ammonium hydroxide i.e. NH_{4}OH

The chemical reaction is given by:

NH_{3}+H_{2}O\rightarrow NH_4OH

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.


8 0
3 years ago
Breaking down earths surface
tino4ka555 [31]

☁️ Answer ☁️

Thats called weathering.

Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth.

Hope it helps.

Have a nice day noona/hyung!~  ̄▽ ̄❤️

6 0
2 years ago
Question 1 Multiple Choice Worth 2 points)<br> (03.05 LC)<br> Which statement is true?
Tasya [4]

Answer:

I need more information. What is the question?

7 0
3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

3 0
3 years ago
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