Answer:
Vf = 4.77 m/s
Explanation:
During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height = 1.16 m
Vf = Final Velocity of Ball = ?
Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)
Therefore, using these values in the equation, we get:
(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²
Vf = √(22.736 m²/s²)
<u>Vf = 4.77 m/s</u>
Answer:
227 m/s
Explanation:
Kinetic energy formula:
- where m = mass of the object (kg)
- and v = speed of the object (m/s)
Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.
First convert the mass to kilograms:
Plug known values into the KE formula.
Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.
First convert the mass to kilograms:
Plug known values into the KE formula.
The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.