We know the equation
weight = mass × gravity
To work out the weight on the moon, we will need its mass, and the gravitational field strength of the moon.
Remember that your weight can change, but mass stays constant.
So using the information given about the earth weight, we can find the mass by substituting 100N for weight, and we know the gravity on earth is 10Nm*2 (Use the gravitational field strength provided by your school, I am assuming yours in 10Nm*2)
Therefore,
100N = mass × 10
mass= 100N/10
mass= 10 kg
Now, all we need are the moon's gravitational field strength and to apply this to the equation
weight = 10kg × (gravity on moon)
We are asked to solve for the acceleration with the given graph in the problem. Let us recall that the formula for acceleration is shown below:
acceleration (a) = (Vf - Vi) / t
in this problem, we need to pick velocity final and initial such as:
Vf = 10 m/s
Vi = 8 m/s
Check the corresponding time, in this case, the time is (40seconds - 30seconds) equivalent to 10 seconds
Solving for the acceleration, we have it:
a = (10 - 8) / 10
a = 2/10
a = 0.2 m/s²
The answer is 0.2 m/s².
Answer:
Using Faraday's law;
ε= -N ∆ψ(B)/ ∆t;
∆t= -N ∆ψ(B)/ ε
Explanation:
Using Faraday's law; Faraday's law state that the induced emf is directly proportional to the rate of change of time of magnetic flux
ε= -N ∆ψ(B)/ ∆t;
Where ε= induced EMF, ∆ψ(B)/ ∆t is the rate of change of magnetic flux, ψ(B) = BA cos θ
θ= the angle between the magnetic field B and the normal surface area.
We can also calculate the direction of induced magnetic flux. At first, the field is perpendicular to the plane of the loop,the loop can rotate about either an horizontal or vertical axis passing through the mid point
Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
