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Leona [35]
3 years ago
12

Two plane mirrors are facing each other. They are parallel, 6 cm apart, and 24 cm in length, as the drawing indicates. A laser b

eam is directed at the top mirror from the left edge of the bottom mirror. What is the smallest angle of incidence with respect to the top mirror, such that the laser beam hits the mirrors in each way
Physics
2 answers:
Strike441 [17]3 years ago
7 0

Answer:

86degrrss

Explanation:

tan L =BC/AB

= 3/12 = 1/4

L= tan^-1 0.25

=4.0 degrees

= 90-4= 86degrees

Sophie [7]3 years ago
6 0

Answer: 33.69 degrees

Explanation:

Given

Distance between the two mirrors, = 6 cm

Length of the two mirrors, = 24 cm

Assuming the laser is shone from just clear of the left edge of the bottom mirror,

a)

Tan L = (O/A)

Tan L = (6 / 12)

Tan L = 0.5

L = Tan^-1 (0.5)

L = 26.57 degrees

(90 - 26.57) = 63.43 deg. to the normal.

Tan L = (6 / [24/6])

Tan L = (6 / 4)

Tan L = 1.5

L = Tan^-1 (1.5)

L = 56.31 degrees

(90 - 56.31) = 33.69 deg. to the normal.

Thus, the angle at which, with respect to the mirror, the laser beam hits the mirrors in each way is 33.69 degrees

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A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 12 A, while that
andreev551 [17]

Answer:

a) 1450watts

b) 564watts

c) 1.11

Explanation:

Power consumed = IV

I is the current rating

V is the operating voltage

If a blow-dryer and a vacuum cleaner each operate with a voltage of 120 V and the current rating of the blow-dryer is 12 A, while that of the vacuum cleaner is 4.7 A then their individual power rating is calculated thus;

a) For blow-dryer

Operating voltage = 120V

Its current rating = 12A

Power consumed = IV

= 120×12

= 1440watts

b) For vacuum cleaner:

Operating voltage is the same as that of blow dryer = 120V

Its current rating = 4.7A

Power consumed = IV

= 120×4.7

= 564watts

c) Energy used = Power consumed × time taken

Energy used = Power × time

Energy used by blow dryer = 1440×20×60

= 1,728,000Joules

Energy used up by vacuum cleaner = 564×46×60

= 564×2760

= 1,556,640Joules

Ratio of the energy used by the blow-dryer in 20 minutes to the energy used by the vacuum cleaner in 46 minutes will be 1,728,000/1,556,640 = 1.11

4 0
3 years ago
Electrolytes serve several purposes in the body, including _________
vfiekz [6]

Answer:

Nerve and muscle function and fluid balance

Explanation:

:)

4 0
2 years ago
A uniform 2.50m ladder of mass 7.30kg is leaning against a vertical wall while making an angle of 51.0degree with the floor. A w
Zigmanuir [339]

Answer:

19.95 J

Explanation:

The center of mass of the ladder is initially at a height of:

h_1=\frac{L}{2}sin\theta

The center of mass of the ladder ends at a height of:

h_2= \frac{L}{2}sin90 =L/2

So, the work done is equal to the change in potential energy which is:

W = PE = mg(h_2-h_1)

now h_2-h_1= 1-sin\theta

therefore

W = [mgL/2]×[1 - sin(theta)]

W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]

solving this we get

W = 19.95 J

8 0
3 years ago
A harmonic oscillator starts with an amplitude of 20.0 cm. After 10.0 s, the amplitude decreases to 15.0 cm. If the linear dampi
tia_tia [17]

Answer: the amount of mass is oscillating is 34.8 kg

Explanation:

Given that;

amplitude A = 20.0 cm

time t = 10 s

amplitude decreases x = 15.0 cm

damping coefficient b = 2.00 N.s/m

amount of mass is oscillating = ?

we know that; amplitude can be expressed as;

x = Ae^-(∝t)

we substitute

15 = 20e^-∝(10)

∝ = 0.02877 s⁻¹

Hence mass m will be;

m = b/2∝

we substitute

m = (2 N.s/m) / ( 2 × 0.02877 s⁻¹)

m = 34.8 kg

Therefore the amount of mass is oscillating is 34.8 kg

4 0
3 years ago
A 1.3 kg ball drops vertically onto a floor, hitting with a speed of 21 m/s. It rebounds with an initial speed of 9.8 m/s. (a) W
Anarel [89]

Answer:

a) Impulse(J)=40.04 kg.m/s

b)F=2566.66 N

Explanation:

Given that

V_1=21 m/s,V_2=9.8m/s

We know that impulse(J) impulse is a vector quantity

J=P_2-P_1

We know that P=mV

SoJ=m(V_2-V_1)

Now by putting the values

J=1.3(9.8-(-21))

So impulse(J)=40.04 kg.m/s

Force is given as

F=\dfrac{dP}{dt}

or we can say that

F=m\left(\dfrac{v_2-V_1}{dt}\right)

So F=\dfrac{40.04}{0.0156}

F=2566.66 N

3 0
3 years ago
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