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Leona [35]
3 years ago
12

Two plane mirrors are facing each other. They are parallel, 6 cm apart, and 24 cm in length, as the drawing indicates. A laser b

eam is directed at the top mirror from the left edge of the bottom mirror. What is the smallest angle of incidence with respect to the top mirror, such that the laser beam hits the mirrors in each way
Physics
2 answers:
Strike441 [17]3 years ago
7 0

Answer:

86degrrss

Explanation:

tan L =BC/AB

= 3/12 = 1/4

L= tan^-1 0.25

=4.0 degrees

= 90-4= 86degrees

Sophie [7]3 years ago
6 0

Answer: 33.69 degrees

Explanation:

Given

Distance between the two mirrors, = 6 cm

Length of the two mirrors, = 24 cm

Assuming the laser is shone from just clear of the left edge of the bottom mirror,

a)

Tan L = (O/A)

Tan L = (6 / 12)

Tan L = 0.5

L = Tan^-1 (0.5)

L = 26.57 degrees

(90 - 26.57) = 63.43 deg. to the normal.

Tan L = (6 / [24/6])

Tan L = (6 / 4)

Tan L = 1.5

L = Tan^-1 (1.5)

L = 56.31 degrees

(90 - 56.31) = 33.69 deg. to the normal.

Thus, the angle at which, with respect to the mirror, the laser beam hits the mirrors in each way is 33.69 degrees

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Three joggers are running along straight lines as follows: Jogger A, with a mass of 55.2kg, is traveling along the line y=6.00m
frutty [35]

Answer:

L = - 1361.591 k Kgm/s

Explanation:

Given

mA = 55.2 Kg

vA = 3.45 m/s

rA = 6.00 m

mB = 62.4 Kg

vB = 4.23 m/s

rB = 3.00 m

mC = 72.1 Kg

vC = 4.75 m/s

rC = - 5.00 m

then we apply the equation

L =  (mv x r)

⇒  LA = mA*vA x rA = 55.2 *(3.45 i)x(6 j) = (1142.64 k) Kgm/s

⇒  LB = mB*vB x rB = 62.4 *(4.23 j)x(3 i) = (- 791.856 k) Kgm/s

⇒  LC = mC*vC x rC = 72.1 *(- 4.75 j)x(- 5 i) = (- 1712.375 k) Kgm/s

Finally, the total counterclockwise angular momentum of the three joggers about the origin is

L = LA + LB + LC = (1142.64 - 791.856 -1712.375) k  Kgm/s

L = - 1361.591 k Kgm/s

7 0
3 years ago
You indicate that a symbol
Goryan [66]

Answer:

B. over the symbol.

Explanation:

vectors are represented with a symbol carrying an arrow head with also indicates direction

8 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th
elena55 [62]

<u>Answer:</u>

<em>Thunderbird is 995.157 meters behind the Mercedes</em>

<u>Explanation:</u>

It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird  decided to take a pit stop and slows down for 250 m. She spent 5 seconds  in the pit stop.

Here final velocity v=0 \ m/s

initial velocity u= 71 m/s  distance  

Distance covered in the slowing down phase = 250 m

v^2-u^2=2as

a= \frac {(v^2-u^2)}{2s}

a = \frac {(0^2-71^2)}{(2 \times 250)}=-10.082 \ m/s^2

v=u+at

t= \frac {(v-u)}{a}

= \frac {(0-71)}{(-10.082)}=7.042 s

t_1=7.042 s

The car is in the pit stop for 5s t_2=5 s

After restart it accelerates for 350 m to reach the earlier velocity 71 m/s

a= \frac {(v^2-u^2)}{(2\times s)} = \frac{(71^2-0^2)}{(2 \times 370)} =6.81 \ m/s^2

v=u+at

t= \frac{(v-u)}{a}

t= \frac{(71-0)}{6.81}= 10.425 s

t_3=10.425 s

total time= t_1 +t_2+t_3=7.042+5+10.425=22.467 s

Distance covered by the Mercedes Benz during this time is given by s=vt=71 \times 22.467= 1595.157 m

Distance covered by the Thunderbird during this time=250+350=600 m

Difference between distance covered by the Mercedes  and Thunderbird

= 1595.157-600=995.157 m

Thus the Mercedes is 995.157 m ahead of the Thunderbird.

6 0
3 years ago
A student runs 35 m east, then 12 m west. What is the distance run by the student?
lora16 [44]
47m total just add them up 35 + 12 = 47
4 0
3 years ago
Read 2 more answers
Heat is the cause and temperature is an effect.How?​
garik1379 [7]

Answer:

This is your answer(☞゚∀゚)☞

Explanation:

Temperature is a measure of the kinetic energy of motion of the molecules. ... As we add heat to a substance, we speed up the motion of the molecules in substance, hence, we increase their kinetic energy. So as we add heat to a substance, the temperature Increases.

<h3>hope it helps</h3>

✌️✌️(・∀・)

5 0
2 years ago
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