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labwork [276]
4 years ago
5

Why does Refraction occur? What is Refraction?

Physics
2 answers:
Bogdan [553]4 years ago
7 0

Answer:

hey!

your answer is

Refraction of light is when the angle it comes out at is DIFFERENT to the angle it went in at!  

Refraction is the change in the direction of light

Explanation:

hope this  helps

astraxan [27]4 years ago
4 0
The change in direction of a wavepassing from one medium to another caused by its change in speed
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If a set of displacement vectors laid head to tail make a closed polygon, what is the resultant vector?
Papessa [141]

The resultant vector is zero.

Explanation:

When you add displacement vectors using the head to tail method, you follow this procedure:

- Draw the first vector

- Draw the second vector, with its tail starting from the head of the first vector

- Draw the third vector, with its tail starting from the head of the second vector

.. and so on.

The resultant of the all vectors will be the vector connecting the tail of the 1st vector to the head of the last vector.

In this problem, the vectors make a closed polygon: this means that the head of the last vector coincides with the tail of the first vector.

Therefore, this means that the length of the resultant vector is zero.

Learn more about vector addition:

brainly.com/question/11220787

brainly.com/question/2892784

#LearnwithBrainly

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3 years ago
Does an athlete do work on a trophy as she lifts it overhead
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No she/he is doing work for her muscles
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3 years ago
A boy pushes a 54kg cart with a force of 81N. What is the cart's acceleration?
borishaifa [10]

Explanation:

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3 years ago
Answer the question and fill in the blank.
maria [59]

Answer:

field goal

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8 0
3 years ago
An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the
garik1379 [7]

(a) 6.04 rev/s

The speed of the ball is given by:

v=\omega r

where

\omega is the angular speed

r is the distance of the ball from the centre of the circle

In situation 1), we have

\omega=8.13 rev/s \cdot 2\pi = 51.0 rad/s

r = 0.600 m

So the speed of the ball is

v=(51.0 rad/s)(0.600 m)=30.6 m/s

In situation 2), we have

\omega=6.04 rev/s \cdot 2\pi = 37.9 rad/s

r = 0.900 m

So the speed of the ball is

v=(37.9 rad/s)(0.900 m)=34.1 m/s

So, the ball has greater speed when rotating at 6.04 rev/s.

(b) 1561 m/s^2

The centripetal acceleration of the ball is given by

a=\frac{v^2}{r}

where

v is the speed

r is the distance of the ball from the centre of the trajectory

For situation 1),

v = 30.6 m/s

r = 0.600 m

So the centripetal acceleration is

a=\frac{(30.6 m/s)^2}{0.600 m}=1561 m/s^2

(c) 1292 m/s^2

For situation 2 we have

v = 34.1 m/s

r = 0.900 m

So the centripetal acceleration is

a=\frac{v^2}{r}=\frac{(34.1 m/s)^2}{0.900 m}=1292 m/s^2

5 0
3 years ago
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