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3 years ago

( Pennfoster plz help )

Physics

2 answers:

Talja [164]3 years ago

7 0

<em>Choice-C </em>is nonsense.

Electrons positioned closer to the nucleus are closer to the protons in the nucleus and more strongly attracted to them. Therefore these electrons are LESS likely to be discharged from the atom than electrons farther away from the nucleus are.

Mnenie [13.5K]3 years ago

4 0

I would say C i'm not 100% sure

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Aliun [14]

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3 years ago

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Which of the following objects has the greatest kinetic energy?

Verizon [17]

Answer:

a baseball flying through the air at 90 miles per hour

Explanation:

For the question, Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If the velocity is doubled the kinetic energy will increase by a factor of four.

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3 years ago

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Which property of light would provide evidence for the idea that light is a wave?

Lena [83]

Color property of light would provide evidence for the idea that light is a wave

<h3><u>Explanation:</u></h3>

The reality is that light manifests practices that are representative of both waves and particles. Young proposed that light of varying colors was formed of waves possessing various lengths, a basic theory that is popularly believed today. In contradiction, the particle theory advocates envisioned that several colors were obtained from particles holding either various masses or moving at various speeds.

All waves are perceived to experience refraction when they transpire from one means to another means. Light, similar to any wave, is apprehended to refract as it transfers from one medium into another medium.

5 0

3 years ago

A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's

blondinia [14]

Answer:

a) $z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

b) $v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

Explanation:

The particle position is given by:

$z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0$

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

$z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

Part b

For this case we can find the average velocity with the following formula:

$v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

8 0

3 years ago

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba

PolarNik [594]

Answer:

If air resistance is taken as negligible, then the ball is in freefall the moment it is thrown so gravity is the only force acting on the object. If air resistance is not negligible then gravity will be the greatest force acting on the ball while it is going up and coming down, because Fair has to be less than gravity at all times otherwise the atmosphere would wither away.

3 0

3 years ago