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andre [41]
3 years ago
13

Decide whether each molecule is stable or not. decide whether each molecule would be diamagnetic or paramagnetic. calculate each

molecule bond order.
Chemistry
1 answer:
astra-53 [7]3 years ago
5 0
Incomplete question?
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CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE
hjlf
The atomic number? If you mean in an atom, then the number of protons is the atomic number or proton number of an atom
6 0
3 years ago
How many moles are in 42.1 grams of NaCl?​
vovikov84 [41]

Answer:

0.71

Explanation:

The molecular mass of NaCl is, 23+35.5

= 58.5

1 mole means molecular mass (in gram)

In 58.5 gm NaCl there is 1 mole.

So, 42.1 gm NaCl contains 42.1/58.5 =0.71 moles.

4 0
3 years ago
The function of ribosomal RNA (rRNA) is
mr Goodwill [35]

Answer:

Its responsible for the process known as translation, or the process our cells use to make proteins.They are also responsible for reading the order of Amino acids and linking them together.

Hope it helps!

6 0
3 years ago
Use the balanced chemical equation below. How many grams of the product are formed when 2.34 g of sulfur is completely reacted w
levacccp [35]

Answer:

7.89 g

Explanation:

Step 1: Write the balanced equation

S₈ + 16 F₂(g) → 8 SF₄

Step 2: Calculate the moles corresponding to 2.34 g of S₈

The molar mass of S₈ is 256.52 g/mol.

2.34g \times \frac{1mol}{256.52g} = 9.12 \times 10^{-3} mol

Step 3: Calculate the moles of SF₄ produced from 9.12 × 10⁻³ mol of S₈

The molar ratio of S₈ to SF₄ is 1:8. The moles of SF₄ produced are 8/1 × 9.12 × 10⁻³ mol = 0.0730 mol

Step 4: Calculate the mass corresponding to 0.0730 moles of SF₄

The molar mass of SF₄ is 108.07 g/mol.

0.0730 mol \times \frac{108.07 g}{mol} = 7.89 g

7 0
4 years ago
a balloon contains 30.0 L of helium gas at 103 kPA. what is the volume of the helium when the balloon rises to an altitude where
stiv31 [10]
Answer:
                V₂  =  123.6 L

Explanation:

According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,

                                                P₁ V₁  =  P₂ V₂     ----- (1)
Data Given;
                   P₁  =  103 kPa

                   V₁  =  30 L

                   P₂  =  25 kPa

                   V₂  =  ?

Solution:

Solving equation 1 for V₂,

                                        V₂  =  P₁ V₁ / P₂

Putting values,
                                        V₂  =  (103 kPa × 30 L) ÷ 25 kPa

                                        V₂  =  123.6 L

Result:
           As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
8 0
3 years ago
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