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Taya2010 [7]
3 years ago
8

If there is no outside force acting on an object that is in motion, can its motion change? Will it stop? Explain your answer.

Physics
2 answers:
fredd [130]3 years ago
8 0

Answer:

yes for both.

Explanation:

according to Newton's first law an object in motion will stay in motion until acted on by an outside force and an object at rest will stay at rest until acted on by an outside force. this means that an object that is moving will stay moving in the direction that it's moving and at the same speed unless there's an outside force acting on it and it will keep in motion until there is an outside force acting on it.

AveGali [126]3 years ago
5 0
The motion can change and it also can stop from gravitational force
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Una muestra de 500g de agua se calienta desde 10°C hasta 80°C. Calcula la cantidad de calor absorbido por líquido si su calor es
weeeeeb [17]

Answer:

Q = 142.324kJ

Explanation:

Data:

M = 500g = 0.5kg

T1 = 10°C = (10 + 273.15)K = 285.15K

T2 = 80°C = (80 + 273.15)K = 353.15K

Q = ?

C = 4186J/kg.K

Q = mc(T2 - T1)

Q = 0.5 * 4186 * (353.15 - 285.15)

Q = 0.5 * 4186 * 68

Q = 142324J

Q = 142.324kJ.

7 0
3 years ago
A radio-controlled car increases its kinetic energy from 3 J to 10 J over a distance of 1 m. What was the average net force on t
goldfiish [28.3K]

Answer:

Net force, F = 7 N

Explanation:

It is given that,

Initial kinetic energy of the car, K_i=3\ J

Final kinetic energy of the car, K_f=10\ J

Distance, d = 1 m

We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :

W=\Delta K

W=K_f-K_i

Also, W = F.d    d = distance and F = net force

F.d=K_f-K_i

F=\dfrac{K_f-K_i}{d}

F=\dfrac{10\ J-3\ J}{1\ m}

F = 7 Newton

So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.

8 0
3 years ago
10. What is the a) Period and b) frequency of a mass spring system using a 12 kg mass and a spring with a k value of 2200N/m?
harkovskaia [24]

Answer:

Part a)

Time period of spring block system is

T = 0.464 s

Part b)

Frequency of spring block system is

f = 2.15 Hz

Explanation:

As we know that the time period of spring mass system is given as

T = 2\pi\sqrt{\frac{M}{k}}

now we have

M = 12 kg

k = 2200 N/m

now we have

T = 2\pi\sqrt{\frac{12}{2200}}

T = 0.464 s

Part b)

As we know that time period of spring block system is inversely dependent on the frequency

so we have

f = \frac{1}{T}

f = \frac{1}{0.464}

f = 2.15 Hz

3 0
3 years ago
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