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Alenkinab [10]
3 years ago
10

A man weighs 650 N. Inside a moving elevator, the floor exerts an upward force of 620 N on the man. What is the magnitude and di

rection of the man's acceleration?
Physics
2 answers:
nikitadnepr [17]3 years ago
6 0

Given that,

Weight of man, W= 650 N

Upward force by elevator, F= 620 N

a = ?

Since,

W = mg

m= W/g =650/9.81

m = 66.25 kg

Since,

F = ma

a = F/m

a = 620/66.25

a = 9.35 m/s²

Acceleration will be 9.35 m/s².

Since the force is in upward direction, it will accelerate the body in upward direction.

cestrela7 [59]3 years ago
3 0

Answer:Man's acceleration is 0.452 \frac{m}{s^{2}} in downward direction

Explanation:

<em>Weight of man, W= 650 N</em>

<em>Normal force exerted by floor of elevator , N= 620 N</em>

<em>Since weight , W = mg</em>

<em>mass m= \frac{W}{g}=\frac{650}{9.8}kg</em>

<em>Using Newtons 2nd law</em>

<em>W-N= ma     where a= acceleration of man in the downward direction</em>

=> 650-620=\frac{650}{9.8}kg\times a

=> a= 0.452 \frac{m}{s^{2}} <em>in downward direction </em>

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<h3>What do you mean by hall voltage ?</h3>

The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.

We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.

lof4

First we have to plot those point Then we can use some computer program to fit those point linearly to get slope

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As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a

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a=\frac{I}{nqt} \\t=\frac{I}{anq} \\t=\frac{.200A}{100X10^{-6}X 1.6 X10^{-19}X10^{26}  } \\t=0.125mm

To learn more about the hall voltage , Visit: brainly.com/question/19130911

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