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Alenkinab [10]
3 years ago
10

A man weighs 650 N. Inside a moving elevator, the floor exerts an upward force of 620 N on the man. What is the magnitude and di

rection of the man's acceleration?
Physics
2 answers:
nikitadnepr [17]3 years ago
6 0

Given that,

Weight of man, W= 650 N

Upward force by elevator, F= 620 N

a = ?

Since,

W = mg

m= W/g =650/9.81

m = 66.25 kg

Since,

F = ma

a = F/m

a = 620/66.25

a = 9.35 m/s²

Acceleration will be 9.35 m/s².

Since the force is in upward direction, it will accelerate the body in upward direction.

cestrela7 [59]3 years ago
3 0

Answer:Man's acceleration is 0.452 \frac{m}{s^{2}} in downward direction

Explanation:

<em>Weight of man, W= 650 N</em>

<em>Normal force exerted by floor of elevator , N= 620 N</em>

<em>Since weight , W = mg</em>

<em>mass m= \frac{W}{g}=\frac{650}{9.8}kg</em>

<em>Using Newtons 2nd law</em>

<em>W-N= ma     where a= acceleration of man in the downward direction</em>

=> 650-620=\frac{650}{9.8}kg\times a

=> a= 0.452 \frac{m}{s^{2}} <em>in downward direction </em>

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a ball was projected in such a way that it attained the maximum horizontal distance with a velocity of 20m/s calculate the verti
Eduardwww [97]

Answer:

80m

Explanation:

u=20,R=?,sin theta=1,g=10

R=u²sin2theta/g

R=20²x2/10

R=400x2=800/10

R=80m

7 0
3 years ago
A spotlight on a boat is y = 2.2 m above the water, and the light strikes the water at a point that is x = 8.5 m horizontally di
slava [35]

Answer:

The answer to the question is

The distance d, which locates the point where the light strikes the bottom is   29.345 m from the spotlight.

Explanation:

To solve the question we note that Snell's law states that

The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction

n₁sinθ₁ = n₂sinθ₂

y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and

θ₁ =  14.511 °

n₁ = 1.0003 = refractive index of air

n₂ = 1.33 = refractive index of water

Therefore sinθ₂ =  \frac{n_1sin\theta_1}{n_2}  = \frac{1.003*0.251}{1.33} = 0.1885 and θ₂ = 10.86 °

Since the water depth is 4.0 m we have tanθ₂ = \frac{4}{x_2} or x₂ = \frac{4}{tan\theta_2 } =\frac{4}{tan(10.86)} = 20.845 m

d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.

5 0
3 years ago
The is the the distance between two crests or two troughs on a transverse wave. It is also the distance between compressions or
mixer [17]

Answer:

Wavelength

Explanation:

The wavelength of a transverse wave (where the oscillation occurs perpendicular to the direction of propagation of the wave) is defined as the distance between two consecutive crests ot two consecutive troughs.

In a longitudinal wave, where the oscillation occurs parallel to the direction of propagation of the wave, the wavelength is defined as the distance between two consecutive compressions or between two consecutive rarefactions.

Other important definitions for a wave are:

- Frequency: the number of complete cycles per second

- Period: the time needed for one complete cycle to occur

- Amplitude: the distance between the equilibrium position and the maximum displacement of the wave

7 0
3 years ago
A student carries a very heavy backpack. To lift the backpack off the ground, the student must apply 80 N of force to do so. The
Xelga [282]

The work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

<h3>How to calculate work done?</h3>

Work done is a measure of energy expended in moving an object; most commonly, force times distance.

It is said that no work is done if the object does not move, hence, the work done on an object can be calculated as follows:

Work done = Force × Distance

According to this question, a student carries a very heavy backpack and to lift the backpack off the ground, the student must apply 80 N of force to lift the backpack 1.5 m.

Work done = 80N × 1.5m

Work done = 120J

Therefore, the work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

Learn more about work done at: brainly.com/question/28172139

#SPJ1

8 0
1 year ago
Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is yo
nalin [4]

Answer:

Ok, let's suppose the simplest of the physical changes:

We have an object that is not moving (so it is not accelerated)

and there is change, now the object moves.

Because there was a change, means that there was an acceleration, and by the second Newton's law.

Force equals mass times acceleration:

F = m*a

There must be a force.

So suppose that you pushed the object, then some energy that you had, you transferred it to the object, that now is moving and now has kinetic energy.

Now, is kinda true that in a closed system the total energy is always constant, but it depends on what is our system.

So if we think in our system as you and the object, then in the whole system the energy does not change because the energy that you lost is now on the object, but again, there was a transfer of energy.

So no, your friend is not correct.

3 0
3 years ago
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