Answer:
Explanation:
When we accelerate in a car on a straight path we tend to lean backward because our lower body part which is directly in contact with the seat of the car gets accelerated along with it but the upper the upper body experiences this force later on due to its own inertia. This force is accordance with Newton's second law of motion and is proportional to the rate of change of momentum of the upper body part.
Conversely we lean forward while the speed decreases and the same phenomenon happens in the opposite direction.
While changing direction in car the upper body remains in its position due to inertia but the lower body being firmly in contact with the car gets along in the direction of the car, seems that it makes the upper body lean in the opposite direction of the turn.
On abrupt change in the state of motion the force experienced is also intense in accordance with the Newton's second law of motion.
Answer:
The distance of the object placed on the principal axis from the concave mirror.
Explanation:
In a concave mirror, the nature of the image formed formed by the object placed in front of the mirror depends on the position of the object placed in from of the mirror. It all depends on the distance between the mirror and the object placed on the principal axis.
The closer the object is to the lens, the more larger or magnified the image formed will be. For example an object placed between the focal point and the pole of a concave produces a much larger image than an object placed beyond the centre of curvature of such mirror.
Answer:
![\lambda=1.03\times 10^{-3}\ m](https://tex.z-dn.net/?f=%5Clambda%3D1.03%5Ctimes%2010%5E%7B-3%7D%5C%20m)
Explanation:
Given that,
The energy of the microwave oven is
.
We need to find the wavelength of these photons.
![1.2\times 10^{-3}\ eV=1.2\times 10^{-3}\times 1.6\times 10^{-19}\\\\=1.92\times 10^{-22}\ J](https://tex.z-dn.net/?f=1.2%5Ctimes%2010%5E%7B-3%7D%5C%20eV%3D1.2%5Ctimes%2010%5E%7B-3%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%5C%5C%5C%3D1.92%5Ctimes%2010%5E%7B-22%7D%5C%20J)
The energy of a wave is given by :
![E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bhc%7D%7B%5Clambda%7D%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7Bhc%7D%7BE%7D)
Put all the values,
![\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.92\times 10^{-22}}\\\\\lambda=1.03\times 10^{-3}\ m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B6.63%5Ctimes%2010%5E%7B-34%7D%5Ctimes%203%5Ctimes%2010%5E8%7D%7B1.92%5Ctimes%2010%5E%7B-22%7D%7D%5C%5C%5C%5C%5Clambda%3D1.03%5Ctimes%2010%5E%7B-3%7D%5C%20m)
So, the wavelength of these photon is
.