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Liono4ka [1.6K]
2 years ago
11

After you cross the finish line, you slow down and come to a stop, breathing hard. It takes you 10 seconds to come to a stop. Wh

at is your acceleration?
Physics
1 answer:
Otrada [13]2 years ago
4 0

Acceleration = (change in speed) / (time for the change)

<em>Acceleration =  -- (speed as you crossed the finish line) / (10 seconds)</em>

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The electric field between two parallel plates connected to a 45-volt battery is 500. volts per meter. The distance between the
kotykmax [81]
Electric field = potential difference
                       -----------------------------
                        distance between plates
 
 Distance between plates   =         45
                                                  ----------
                                                     500
 
                                           =          0.09 meters.

8 0
3 years ago
the age of Egyptian pyramid about NTT power 11 years the mankind exist for 29 years how many seconds will be men have exist if a
Zepler [3.9K]

It makes no sense how you typed this problem out.

3 0
3 years ago
What is the force due to gravity of a 38 kg student?
alukav5142 [94]

Answer:

F_g = 372.78 N

Explanation:

Formula for force of gravity is;

F_g = mg

Where;

m is mass

g is acceleration due to gravity

We are given;

Mass = 38 kg

Acceleration due to gravity has a constant value of 9.81 m/s²

Thus;

F_g = 38 × 9.81

F_g = 372.78 N

6 0
3 years ago
What is the period (in hours) of a satellite circling Mars 100 km above the planet's surface? The mass of Mars is 6.42 × 1023 kg
scZoUnD [109]

To solve this problem it is necessary to apply the concepts related to the Centrifugal Force and the Gravitational Force. Since there is balance on the body these two Forces will be equal, mathematically they can be expressed as

F_c = F_g

\frac{mv^2}{r} = \frac{GmM}{r^2}

Where,

m = Mass

G =Gravitational Universal Constant

M = Mass of the Planet

r = Distance/Radius

Re-arrange to find the velocity we have,

v^2 = \frac{GM}{r}

At the same time we know that the period is equivalent in terms of the linear velocity to,

T = \frac{2\pi}{\frac{v}{r}}

v = \frac{2\pi r}{T}

If our values are that the radius of mars is 3400 km and the distance above the planet is 100km more, i.e, 3500km we have,

v^2 = \frac{GM}{r}

( \frac{2\pi r}{T})^2 =  \frac{GM}{r}

T = \sqrt{\frac{4\pi^2 r^3}{GM}}

Replacing we have,

T = \sqrt{\frac{4\pi^2 (3500*10^3)^3}{(6.67430*10^{-11})(6.42*10^23)}}

T = 6285.09s (\frac{1min}{60s})(\frac{1hour}{60min})

T= 1.74hour

Therefore the correct answer is C.

7 0
3 years ago
Please help ASAP please
Alex_Xolod [135]

Answer:

14

Explanation:

6 0
3 years ago
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