Question

The figure shows the electric field inside a cylinder of radius R= 3.2 mm. The field strength is increasing with time as E= 1.4 ×108t2V/m, where t is in s. The electric field outside the cylinder is always zero, and the field inside the cylinder was zero for t<0. Find an expression for magnetic field strength as a function of time at a distance r>R from the center.

Answer 1

The Magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.it is denoted by B.

What is magnetic field strength?

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength

Given

The radius of cylinder is,R=2.8 mm = 0.028 m

$\rm \oint B.ds = \frac{\mu_0 \epsilon_0 d\phi}{dt} \\\\ B \times 2\pi r = \frac{\mu_0 \EPSILON_0 d (EA)i}{dt} \\\\\ b = \frac{\mu_0 \epsilon_0 \times \PI r^ 2 d(E)}{dt} \times \frac{1}{2\pir} \\\\ B= \frac{\mu_0 \epsilon_0 \times rd (E)}{2dt} \\\\ B= \frac{1.26 \times 10^{-5}\times 8.85 \times 10^{-12}\times (3.2 \times 10^{-3})\times 1.4 \times 10^8}{2} \\\\ B =2.4 \times 10^{-11} \ T$

Hence, magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.

To learn more about the strength of induced magnetic field, refer;

brainly.com/question/2248956

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