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evablogger [386]
3 years ago
9

Identify the type of energy involved in each step:

Chemistry
1 answer:
Agata [3.3K]3 years ago
6 0
Radiant energy or electrical energy
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Which of the following statements is a part of John Dalton’s atomic theory?
Phantasy [73]

Answer:

i think it is all atoms of all elements are exactly alike and have the same mass

Explanation:

4 0
3 years ago
In atmospheric chemistry, the following chemical reaction converts SO2, the predominant oxide of sulfur that comes from combusti
Misha Larkins [42]

Answer:

Explanation:

From the given information;

The chemical reaction can be well presented as follows:

\mathtt{SO_{2(g)} + \dfrac{1}{2}O_{2(g)} }  ⇄ \mathtt{3SO_{2(l)}}

Now, K is known to be the equilibrium constant and it can be represented in terms of each constituent activity:

i.e

K = \dfrac{a_{so_3}}{a_{so_2} a_{o_2}^{\frac{1}{2}}}

However, since we are dealing with liquids solutions;

K = \dfrac{1}{\dfrac{Pso_2}{P^0}\Big ( \dfrac{Po_2}{P^0} \Big)^{1/2}}   since the activity of a_{so_3} is equivalent to 1

Hence, under standard conditions(i.e at a pressure of 1 bar)

K = \dfrac{1}{Pso_2Po_2^{1/2}}

(b)

From the CRC Handbook, we are meant to determine the value of the Gibb free energy by applying the formula:

\Delta _{rxn} G^o = \sum \Delta_f \ G^o (products) - \sum \Delta_fG^o (reactants) \\ \\ = (1) (-368 \ kJ/mol) - (\dfrac{1}{2}) (0) - ((1) (-300.13 \ kJ/mol)) \\ \\ = -368 \ kJ/mol + 300.13 \ kJ/mol \\ \\  \simeq -68 \ kJ/mol

Thus, for this reaction; the Gibbs frree energy = -68 kJ/mol

(c)

Le's recall that:

At equilibrium, the instantaneous free energy is usually zero &

Q(reaction quotient) is equivalent to K(equilibrium constant)

So;

\mathtt{\Delta _{rxn} G = \Delta _{rxn} G^o + RT In Q}

\mathtt{0- \Delta _{rxn} G^o = RTIn K } \\ \\ \mathtt{ \Delta _{rxn} G^o = -RTIn K }  \\ \\  K = e^{\dfrac{\Delta_{rxn} G^o}{RT}} \\ \\  K = e^{^{\dfrac{67900 \ J/mol}{8.314 \ J/mol \times 298 \ K}} }

K =7.98390356\times 10^{11} \\ \\  \mathbf{K = 7.98 \times 10^{11}}

(d)

The direction by which the reaction will proceed can be determined if we can know the value of Q(reaction quotient).

This is because;

If  Q < K, then the reaction will proceed in the right direction towards the products.

However, if Q > K , then the reaction goes to the left direction. i.e to the reactants.

So;

Q= \dfrac{1}{Pso_2Po_2^{1/2}}

Since we are dealing with liquids;

Q= \dfrac{1}{1 \times 1^{1/2}}

Q = 1

Since Q < K; Then, the reaction proceeds in the right direction.

Hence, SO2 as well O2 will combine to yield SO3, then condensation will take place to form liquid.

8 0
3 years ago
6.00 moles of sodium perchlorate contains the same number of atoms as __________. 6.00 moles of sodium perchlorate contains the
Ksju [112]

Answer:

6.00 moles of sodium permanganate

Explanation:

Let us attempt to count the number of atoms present in sodium perchlorate. The formula of the compound is NaClO4

Sodium atoms - 1

Chlorine atoms - 1

Oxygen atoms -4

Total number of atoms = 6

Among the options, only KMnO4 also has six atoms. One atom of potassium, one atom of manganese and four atoms of oxygen.

3 0
3 years ago
Explain how scientists use geologic time to determine the age of land forms.
valentina_108 [34]
I am sorry i wish i could help you but i dont know the answer either.
5 0
2 years ago
A critical reaction in the production of energy in biological systems is the hydrolysis of adenosine triphosphate (ATP) to adeno
Archy [21]

Answer:

ΔG° of reaction =  -47.3 x 10^{3} J/mol      

Explanation:

As we can see, we have been a particular reaction and Energy values as well.

ΔG° of reaction = -30.5 kJ/mol

Temperature = 37°C.

And we have to calculat the ΔG° of reaction in the biological cell which contains ATP, ADP and HPO4-2:

The first step is to calculate the equilibrium constant for the reaction:

Equilibrium Constant K = \frac{[HPO4-2] x [ADP]}{ATP}

And we have values given for these quantities in the biological cell:

[HP04-2] = 2.1 x 10^{-3} M

[ATP] = 1.2 x 10^{-2} M

[ADP] = 8.4 x 10^{-3} M

Let's plug in these values in the above equation for equilibrium constant:

K = \frac{[2.1x10^{-3}] x [8.4x10^{-3}] }{[1.2 x 10^{-2}] }

K = 1.47 x 10^{-3} M

Now, we have to calculate the ΔG° of reaction for the biological cell:

But first we have to convert the temperature in Kelvin scale.

Temp = 37°C

Temp = 37 + 273

Temp = 310 K

ΔG° of reaction = (-30.5 10^{3}) + (8.314)x (310K)xln(0.00147)

Where 8.314 = value of Gas Constant

ΔG° of reaction = (-30.5 x 10^{3}) + (-16810.68)

ΔG° of reaction = -47.3 x 10^{3} J/mol

5 0
2 years ago
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