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o-na [289]
2 years ago
8

Write equations for the initiation and propagation steps for the formation of dichloromethane by free radical

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
7 0
 <span>Name of type of mechanism </span>initiation step<span> first </span>propagation step<span> second </span>propagation step<span>(ii) </span>write<span> an overall </span>equation<span> for the </span>formation of dichloromethane<span> from ... Best Answer: i) This is a </span>free-radical<span> substitution mechanism.</span>
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Which gas law refers to the solubility of a gas changing with the pressure over the solution
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Convert 3 mol of Co, to grams.
GuDViN [60]

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Explanation:

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2 years ago
A flask with a volume of 3.16 l contains 9.33 grams of an unknown gas at 32.0°c and 1.00 atm. What is the molar mass of the gas?
Inessa05 [86]

Answer:

73.88 g/mol

Explanation:

For this question we have to keep in mind that the unknown substance is a <u>gas</u>, therefore we can use the <u>ideal gas law</u>:

PV=nRT

In this case we will have:

P= 1 atm

V= 3.16 L

T = 32 ªC = 305.15 ºK

R= 0.082 \frac{atm*L}{mol*K}

n= ?

So, we can <u>solve for "n"</u> (moles):

1~atm*3.16~L~=~n*0.082~\frac{atm*L}{mol*K}*305.15~K

n=\frac{1~atm*3.16~L~}{0.082~\frac{atm*L}{mol*K}*305.15~K}

n=0.126~mol

Now, we have to remember that the <u>molar mass value has "g/mol"</u> units. We already have the grams (9.33 g), so we have to <u>divide</u> by the moles:

molar~mass=\frac{9.33~grams}{0.126~mol}

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