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vitfil [10]
3 years ago
13

-3/4j+1/5=3/6 Can someone help me find j

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

j= -0.4

Step-by-step explanation:

multiply both sides by 60

=45j(+12)=30-12

take the 12 ti the right hand side and the sign changes

= -45j=18 then divide by 45 on both sides

j= -2/5

j= -0.4

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The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?
Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

  • Substitute the values

{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

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3 years ago
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Answer:

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Answer:

Step-by-step explanation:

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The length of a rectangle is five inches less than twice it’s width. If the rectangle has a perimeter of 80 inches, find the len
yawa3891 [41]

Answer:

Width of the rectangle  = 15 inches

Length of the rectangle  = 25 inches

Step-by-step explanation:

Let the width of the rectangle =  k inches

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or  k = 90 / 6

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And the length of the rectangle =  2k -5 = 2 x 25  - 5 = 25 inches

5 0
3 years ago
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