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Ivan
1 year ago
6

What line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration?

Physics
1 answer:
Kaylis [27]1 year ago
7 0

Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

<h3 /><h3>Line of code for force and acceleration</h3>
  • In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
  • Acceleration is a vector quantity (in that they have magnitude and direction).
  • The direction of an object's acceleration is determined by the direction of the net force acting on it.
  • Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
  • The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
  • It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.

def force(mass, acceleration):

force_val = mass*acceleration

return force_val

10 is assigned to mass and 9.81 is assigned to acceleration

def force(10, 9.81)

So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

Learn more about acceleration here:

brainly.com/question/460763

#SPJ4

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Water flows over a section of Niagara Falls at rate of 1.1×10^6 kg/s and falls 49.4 m. How much power is generated by the fallin
DerKrebs [107]

Answer:

<em>The power generated is =  5.33×10⁸ Watt. </em>

Explanation:

Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>

<em>Mathematically,</em>

<em>Power (P) = Work done/time or Energy/time</em>

P = mgh/t............................... Equation 1

P = δgh............................. Equation 2

Where δ = fall rate, g = acceleration due to gravity, h = height.

<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²

Substituting these values into equation 2

P = 1.1×10⁶×49.4×9.81

P = 533.08×10⁶

<em>P = 5.33×10⁸ Watt.</em>

<em>Thus the power generated is =  5.33×10⁸ Watt. </em>

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3 years ago
a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one
prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be 37^oC is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

f=\frac{v_T}{4L}

where, v_T=v\sqrt{\frac{T}{273} }

Since, T=37+273 K = 310 K

v = 331 m/s

\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s

Using this, we get:

f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz

Hence, the fundamental frequency is 367.42 Hz.

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<h3><em><u>Hope it helps you </u></em><em><u>♡</u></em><em><u>♡</u></em></h3>

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