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AnnyKZ [126]
4 years ago
15

Which of the following expressions are correct for impulse?A. mvB. F∆tC. FvD. ∆p

Physics
2 answers:
Oduvanchick [21]4 years ago
8 0

Answer:

impulse = F∆t

Explanation:

Step2247 [10]4 years ago
6 0

Answer:

B. F∆t


D. ∆p

Explanation:

Both formulas are correct. In fact, impulse is defined as the product between the force applied (F) and the time interval in which the force is applied (∆t

):

I = F∆t


So, option B. is correct. However, we see that this expression corresponds also to the change in momentum (option D)

in fact, we can rewrite the force as:

I=(ma)\Delta t

but the acceleration can be rewritten as ratio between change in velocity and change in time:

I=m\frac{\Delta v}{\Delta t} \Delta t=m \Delta v = \Delta p

which corresponds to the change in momentum.

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A spring stretches 0.2 cm per newton of applied force. An object is suspended from the spring and a deflection of 3 cm is observ
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Answer:

m=1.53kg    

Explanation:

To solve this problem we use the Hooke's Law:

F=k*\Delta x     (1)

F is the Force needed to expand or compress the spring by a distance Δx.

The spring stretches 0.2cm per Newton, in other words:

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The force applied is due to the weight

F=mg

We replace in (1):

mg=k*\Delta x  

We solve the equation for m:

m=k*\Delta x/g=5*3/9.81=1.53kg    

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