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Leni [432]
3 years ago
10

a red kangaroo can hop at speeds of 65 km/hr. how much time will it take the kangaroo to hop 0.25 km at that speed?

Physics
1 answer:
daser333 [38]3 years ago
3 0

Time = (distance) / (speed)

Time = (0.25 km) / (65 km/hr)

<em>Time = 0.00385 hour</em>

(That's 13.85 seconds.)

<u />

<u>Better way:</u>

Distance = 0.25 km

Distance = 250 meters

Speed = (65 km/hr) x (1000 m/km) x (1 hr/3600 sec)

Speed = 18.06 m/sec

Time = (250 m) / (18.06 m/s)

<em>Time = 13.85 seconds  </em>

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Part A (4 pts) Consider light of wavelength λ = 670nm traveling in air. The light is incident at normal incidence upon a thin fi
s344n2d4d5 [400]

Answer:

Explanation:

On both sides of the film , the mediums have lower refractive index.

for interfering pattern from above , for constructive interference of reflected wave from both sides of the film , the condition is

2μt = ( 2n +1 ) λ / 2

μ is refractive index of film ,t is thickness of film λ is wavelength of light

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2μt =  λ / 2

t =  λ / 4μ

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6 0
3 years ago
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
andriy [413]

Answer:

K = ρL²g

Explanation:

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Then:

F = upthrust ( restoring force) = weight of the liquid displaced.

F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g

where;

A = L²

\rho_{\omega} = \rho

F = ky.

Then,

Ay \rho g = ky

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3 0
3 years ago
What is the change in momentum of a 50-kg rock that falls freely for 3 seconds?
Elan Coil [88]

Answer:

1470kgm/s

Explanation:

Given parameters:

Mass of the rock = 50kg

Time taken for the free fall  = 3s

Unknown:

Change in momentum = ?

Solution:

The change in momentum will be difference between the ending momentum and finishing momentum.

  Momentum is the product of mass and velocity

       Momentum  = mass x velocity

Initial momentum  = 0, the velocity is 0

Final momentum = mass x final velocity

      let us find the final velocity;

                V = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

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                 V  = 0 + 9.8x3 = 29.4m/s

So;

 Change in momentum  = 50 x 29,4  = 1470kgm/s

6 0
3 years ago
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