Two charged particles are placed 2.0 meters apart. the first charge is +2.0 e-6 c, and the second charge is +4.0 e-6
1 answer:
We can calculate the electrical force between the two charges with Coulomb's law:
Fc=(k*Q₁*Q₂)/r², where k=9*10^9 N m² C⁻², Q₁ and Q₂ are the two charges and r is the distance between the two charges.
Now we simply input the numbers and get:
Fc= { (9*10^9)*(2*10^-6)*(4*10^-6) } / 2²
Fc=0.018 N
The electric force between the charges Q₁ and Q₂ is Fc=0.018 N
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