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photoshop1234 [79]
3 years ago
14

Two charged particles are placed 2.0 meters apart. the first charge is +2.0 e-6 c, and the second charge is +4.0 e-6

Physics
1 answer:
WITCHER [35]3 years ago
8 0
We can calculate the electrical force between the two charges with Coulomb's law: 

Fc=(k*Q₁*Q₂)/r², where k=9*10^9 N m² C⁻², Q₁ and Q₂ are the two charges and r is the distance between the two charges.

Now we simply input the numbers and get:

Fc= { (9*10^9)*(2*10^-6)*(4*10^-6) } / 2²

Fc=0.018 N

The electric force between the charges Q₁ and Q₂ is Fc=0.018 N
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A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.

<h3>How to calculate deceleration ?</h3>

While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.

We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.

The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.

velocity of car = 30 m/s

car need to stop in 50m

Deceleration a = v^2 –  u^2 / 2s

                          = 0^2 - 50^2 / 2*30

                          = 11.56

Deceleration of the care = 11.56 ms−2

To learn more about deceleration refer :

brainly.com/question/75351

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1 year ago
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Answer:

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Explanation:

hope it helps u

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