A sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C will have the same average kinetic energy of benzene molecules.
Let us recall that the average kinetic energy of molecules depends on the molar mass of the substance as well as the temperature of the substance. We have that;
average kinetic energy=
R = gas constant
NA =Number of molecules
M = Temperature in Kelvin
We can see that the average kinetic energy depends on temperature therefore, a sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C will have the same average kinetic energy of benzene molecules.
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Answer:
The percent yield of chloro-ethane in the reaction is 82.98%.
Explanation:
Moles of ethane =
Moles of chlorine gases =
As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.
This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.
According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.
Then 9.1549 moles of chlorien gas will give:
of chloro-ethane
Mass of 9.1549 moles of chloro-ethane:
9.1549 mol × 64.5 g/mol = 590.4910 g
Theoretical yield of chloro-ethane: 590.4910 g
Given experimental yield of chloro-ethane: 490.0 g
The percent yield of chloro-ethane in the reaction is 82.98%.
First, determine the amount of vinegar in grams by multiplying the volume by the density. That is,
mass = (355 ml) x (1.01 g/mL) = 358.55 g
Then, multiply the calculated mass above by the decimal equivalent of the given percentage above.
amount of acetic acid = (358.55 g)(0.0602) = 21.58 g
The answer for this question is niche.
Answer:
it just shows a black screen
Explanation: