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never [62]
2 years ago
15

Two carts (m= 0.4 kg each) are placed on an aluminum track. The first cart pushed with the initial velocity of 1.5 m/s towards t

he second cart, which remains at rest until the collision. Determine the velocities if both carts after the collision.
Physics
1 answer:
Lorico [155]2 years ago
5 0

here two cars are placed on an aluminium track

so there is no friction on two carts during their motion and hence there is no external force on them

now if there is no external force so momentum is conserved

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f]

here

m_1 = m_2 = 0.4 kg

v_{1i} = 1.5 m/s

v_{2i} = 0

now plug in all values in it

0.4 * 1.5 + 0 = 0.4* v_{1f} + 0.4*v_{2f}

divide whole equation by mass 0.4

v_{1f} + v_{2f} = 1.5

also be the equation of coefficient of restitution

e = 1 = \frac{v_{2f} - v_{1f}}{v_{1i} - v_{2i}}

now we have

v_{2f} - v_{1f} = 1.5

now by solving above equations we will have

v_{2f} = 1.5 m/s

v_{1f} = 0

so after collision speed of two carts is 0 m/s and 1.5 m/s after collision

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,000 km above the surface of the earth, and we assume it has an isotropic power output of 1 kW (although, in practice, satellite antennas transmit signals that are less powerful but more directional).

Reception devices pick up the variation in the electric field vector of the electromagnetic wave sent out by the satellite. Given the satellite specifications listed in the problem introduction, what is the amplitude E0 of the electric field vector of the satellite broadcast as measured at the surface of the earth? Use ϵ0=8.85×10^−12C/(V⋅m) for the permittivity of space and c=3.00×10^8m/s for the speed of light.

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The electric field vector of the satellite broadcast as measured at the surface of the earth is  E_o = 6.995 *10^{-6} \ V/m

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     The height of the satellite is  r  = 35000 \ km  =  3.5*10^{7} \ m

      The power output of the satellite is P  = 1 \ KW  =  1000 \ W

       

Generally the intensity of the electromagnetic radiation of the satellite at the surface of the earth is  mathematically represented as  

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          I  =  c * \epsilon_o * E_o^2

Where E_o is the amplitude of the electric field vector of the satellite broadcast so

         E_o =  \sqrt{\frac{2 * I}{c * \epsilon _o} }

substituting values

          E_o =  \sqrt{\frac{2 * 6.495 *10^{-14}}{3.0 *10^{8} * 8.85*10^{-12}} }

           E_o = 6.995 *10^{-6} \ V/m

 

   

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