Answer:
187 J
Explanation:
First Law of Thermodynamics :
ΔQ = ΔW + ΔU
ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.
ΔW : Work. If it done by the system then positive and if it is done on system then negative.
ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.
ΔQ = 79 J
ΔW = - 108 J
ΔU = ?
substituting the value in the equation:
79 = -108 + ΔU
∴ ΔU = 187 J
Answer:
Take the numbers and fill them in graph.
Plot time as X and speed as Y and afterward join then like a line graph.
After one meter, 3.4% of the light is gone ... either soaked up in the fiber
material or escaped from it. So only (100 - 3.4) = 96.6% of the light
remains, to go on to the next meter.
After the second meter, 96.6% of what entered it emerges from it, and
that's 96.6% of 96.6% of the original signal that entered the beginning
of the fiber.
==> After 2 meters, the intensity has dwindled to (0.966)² of its original level.
It's that exponent of ' 2 ' that corresponds to the number of meters that the light
has traveled through.
==> After 'x' meters of fiber, the remaininglight intensity is (0.966) ^x-power
of its original value.
If you shine 1,500 lumens into the front of the fiber, then after 'x' meters of
cable, you'll have
<em>(1,500) · (0.966)^x</em>
lumens of light remaining.
=========================================
The genius engineers in the fiber design industry would not handle it this way.
When they look up the 'attenuation' of the cable in the fiber manufacturer's
catalog, it would say "15dB per 100 meters".
What does that mean ? Break it down: 15dB in 100 meters is <u>0.15dB per meter</u>.
Now, watch this:
Up at the top, the problem told us that the loss in 1 meter is 3.4% . We applied
super high mathematics to that and calculated that 96.6% remains, or 0.966.
Look at this ==> 10 log(0.966) = <em><u>-0.15</u> </em> <== loss per meter, in dB .
Armed with this information, the engineer ... calculating the loss in 'x' meters of
fiber cable, doesn't have to mess with raising numbers to powers. All he has to
do is say ...
-- 0.15 dB loss per meter
-- 'x' meters of cable
-- 0.15x dB of loss.
If 'x' happens to be, say, 72 meters, then the loss is (72) (0.15) = 10.8 dB .
and 10 ^ (-10.8/10) = 10 ^ -1.08 = 0.083 = <em>8.3%</em> <== <u>That's</u> how much light
he'll have left after 72 meters, and all he had to do was a simple multiplication.
Sorry. Didn't mean to ramble on. But I do stuff like this every day.
Answer:
unknow e and f
Explanation:
In experiments with alpha particles that are obtained by the method of radioactive decay of atoms, some parameters are known
a) Known. The initial velocity is given by the energy of the particles entities by the atomic nuclei
b) Known. The particle charge always 2e, helium core
c) Known. It is set in the given experiment, in general it is selected as zero
d) Known. Placed by the experimenter
e) Unknown. The speed depends on the interactions with the system
f) Unknown. It depends on the interactions with the system, because the position depends on the interactions
g) Known. It is always the value of a helium nucleo
Answer:
y = 17,89 m
Explanation:
Let us fixate the reference point in top of the building, from where the watermelon is thrown down. We will assume also that the positive axis of our system points up. We describe the watermelon’s motion with the equation:
Clearing the equation so we isolate y we have that:
Making a substitution with the values from the statement we have:
]
So, this skyscraper is about 17,89 m tall; which is not very tall for a skyscraper but who am I to judge. 17,89 m is also the displacement of the watermelon from the point it was thrown down.
I hope everything was clear with my explanation. If I can help with anything else, just let me know. Have an awesome day :D
