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Amanda [17]
3 years ago
10

The answer is A and no matter how many times I tried I can't get it.

Physics
1 answer:
ryzh [129]3 years ago
5 0
Imagine a skinny straw in the water, standing right over the hole. The WEIGHT of the water in that straw is the force on the tape. Now, the volume of water in the straw is (1 mm^2) times (20 cm). Once you have the volume, you can use the density and gravity to find the weight. And THAT's the force on the tape. If the tape can't hold that force, then it peels off and the water runs out through the hole. /// This is a pretty hard problem, because it involved mm^2, cm, and m^3. You have to be very very very careful with your units as you work through this one. If you've been struggling with it, I'm almost sure the problem is the units.
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n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

Explanation:

In point i:

T_{theo}= 2\pi \sqrt{\frac{l}{g}}

        =2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s

If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
3 years ago
What's a difference between mercury and oxygen?<br> (They both are elements)
borishaifa [10]

--  There are 80 protons in the nucleus of every atom of Mercury,
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--  Mercury must be colder than -39°C in order to freeze, but Oxygen
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--  Oxygen is required for human life.  Mercury is a deadly poison.

8 0
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a 150 kg object takes a 1.5 minute travel to a 2500 straight path it begins you trip at traveling 120 miles an hour and it decel
crimeas [40]
I believe it’s acceleration is -1.11 m/s^2
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chuck wagon travels with a constant velocity of 0.5 mile/minutes. determine the total distance traveled by Chuck Wagon during 12
n200080 [17]

Given:

Velocity: 0.5 mile/minute

Time: 12 minute

Now we know that speed and velocity have the same magnitude. Hence speed=velocity=0.5 mile/min

Substituting the given values in the above formula we get

Distance = 0.5 x 12= 6 miles

7 0
3 years ago
41. 2072 Set E Q.No. 11 A source of sound produces a note of
Nimfa-mama [501]
A. is the answer for this
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