Answer:
recall that heat absorbed released is given by
Q = mc*(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (in J/g-k)
T = temperature (in C or K)
*note: Q is (+) when heat is absorbed and (-) when heat is released.
substituting,
Q = (480)*(0.97)*(234 - 22)
Q = 98707 J = 98.7 kJ
Explanation:
When two charged plates are separated by a distance, the potential difference between the plates is 54 Volts.
<h3>What is uniform electric field?</h3>
The electric field intensity which does not increase or decrease with time or remain constant is called the uniform electric field.
Given is the plates separated by distance d = 15 cm =0.15 m, electric field E= 360 N/C.
The relation between the electric field and voltage is
E=V/d
Substitute the values into the expression to get the potential difference V,
V = 360 x 0.15
V = 54 Volts
Thus, the potential difference between the plates is 54 Volts.
Learn more about uniform electric field.
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Using
KE = ½mv² = ½×1500×19×19 = 270750 joules