Answer:
9.80g of O2.
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
2KClO3 —> 2KCl + 3O2
Step 2:
Determination of the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:
Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol
Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96g.
From the balanced equation above, 245g of KClO3 decomposed to produce 96g of O2.
Step 3:
Determination of the mass of O2 produced in the decomposition of 25.0g of KClO3. This is illustrated below:
From the balanced equation above, 245g of KClO3 decomposed to produce 96g of O2.
Therefore, 25g of KClO3 will decompose to produce = (25x96)/245 =
9.80g of O2.
Therefore, 9.80g of O2 is produced from the decomposition of 25g of KClO3.
