The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.
<h3>What is electric file strength?</h3>The electric field strength is defined as the ratio of electric force and charge.
The electric field strength is found as;
Hence, the electric field strength will be 0.6252 V/m.
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Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
in eV you have:
The kinetic energy of the proton is 1.29eV
To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:
Where,
G = Gravitational constant
M = Mass of earth (in this case)
m = mass of satellite
r = radius
In the other hand we have the second's newton law:
Where,
m = mass
a = acceleration
Equation both equations we have,
For the problem we have that,
<em>Satellite A:</em>
<em>Satellite B:</em>
The ratio between the two satellites would be,
Solving for a_B,
Therefore the centripetal acceleration of is a quarter of