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DerKrebs [107]
3 years ago
15

Dr. West mixes zinc (Zn) and hydrochloric acid (HCl) together in his laboratory. The two chemicals react to form hydrogen gas (H

2) and zinc chloride (ZnCl2).
Which of the following are products in the chemical reaction described above?
A.
hydrogen gas and zinc chloride
B.
zinc and hydrochloric acid
C.
hydrochloric acid and zinc chloride
D.
zinc and hydrogen gas
Physics
2 answers:
Dovator [93]3 years ago
5 0

Answer: A.  hydrogen gas and zinc chloride

Explanation: Reactants of a chemical reaction is defined as the substances which take part in a chemical reaction and undergoes a chemical change. Reactants are written on left side of the arrow.

Products are defined as the substance which are formed at the end of the chemical reaction.Products are written on the right side of the arrow.

For the reaction of zinc (Zn) and hydrochloric acid (HCl), the balanced chemical equation is represented as :

Zn+2HCl\rightarrow ZnCl_2+H_2

Here, ZnCl_2 and H_2 are products.

svp [43]3 years ago
4 0

Answer :

A : hydrogen gas and zinc chloride

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Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli
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Answer:

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

Explanation:

Given:

Mass of  Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = v_{f}=?

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}

Substituting the values we get

2\times 14 + 5\times 0 =(2+5)\times v_{f}

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Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

8 0
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