Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p
1 answer:
Answer:
The force exerted on the is
Explanation:
From the question we are told that
The area is
The magnitude of charge placed on them is
The charge placed between the plate is
The electric field generated around the plate is mathematically represented as
Substituting values
The force exerted the charge is mathematically represented as
Substituting values
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An elevator has 750,000 J when it is lived 500 meters in the air
Answer: Option D
<u>Explanation:</u>
The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as
Where,
m – mass of object
Acceleration due to gravity =
h = 500 meters
Force = 1500 Newton
As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as
Hence, an elevator has 750,000 J when it is lived 500 meters in the air.
Answer:
68 m
Explanation:
Given that the horizontal velocity of the birdman = 17 m/s and
the height, h= 78 m.
The gravitational force is acting in the downward direction, so it will not change the horizontal speed.
The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.
Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, m/s.
In the vertical direction, u = 0,
The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e
s= 78 m
Let t be the time taken to cover a distance of 78 m.
Now, applying the equation of motion in the vertical direction,
where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.
Here, , so
seconds.
Hence, the time taken to reach the ground is 4 seconds.
As the horizontal speed, m/s, is constant throughout the journey, so
the horizontal distance covered by turd
m.
So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly above the start of the field.
Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.