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Naddik [55]
4 years ago
13

What is a population?

Physics
1 answer:
maks197457 [2]4 years ago
7 0

Answer:

A

Explanation:

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The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde
boyakko [2]

Explanation:

Given data:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Distance d between the plates = 1 mm = 1×10⁻³m

Voltage of the battery is emf = 100 V

Resistance = 1025 ohm

Solution:

In RC circuit, the voltage between the plates is related to time t. Initially the voltage is equal to that of battery V₀ = emf = 100V. But After time t the resistance and capacitor changes it and the final voltage is V that is given by

V = V_{0}(1-e^{\frac{-t}{RC} }  )\\\frac{V}{V_{0} } = 1-e(^{\frac{-t}{RC} })  \\e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }

Taking natural log on both sides,

e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }  \\\frac{-t}{RC} = ln(1-\frac{V}{V_{0} } )\\t = -RCln(1 - \frac{V}{V_{0} })

t = -RC ln (1-\frac{V}{V_{0} })        (1)

Now we can calculate the capacitance by using the area of the plates.

C = ε₀A/d

  = \frac{(8.85*10^{-12))} (20*10^{-4}) }{1*10^{-3} }

  = 18×10⁻¹²F

Now we can get the time when the voltage drop from 100 to 55 V by putting the values of C, V₀, V and R in the equation (1)

t = -RC ln (1-\frac{V}{V_{0} })

 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

5 0
3 years ago
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