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Georgia [21]
3 years ago
7

A sample of diborane gas has a pressure of 345 torr at a temperature of -15c and volume of 3.48L if conditions are changed so th

at the temperature is 36c and the pressure is 468 torr what will be the volume of the sample
Chemistry
1 answer:
kap26 [50]3 years ago
4 0

Answer: 3.05L= V2

Explanation:

using

P1V1/T1=P2V2/T2

where p1= 345torr

T1, tempertaure= -15c+ 273=258K

T2, temperature= 36+ 273=309K

p2, Pressure= 468 torr

V2=???

P1V1/T1=P2V2/T2

v2=P1V1T2/T1P2= 345X3.46L X 309/ 258X 468=

V2=  3.05L

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Explanation:

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What activates a convection current, starting the flow of a fluid ??
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8 0
2 years ago
A 30.0-g piece of metal at 203oC is dropped into 400.0 g of water at 25.0 oC. The water temperature rises to 29.0 oC. Calculate
oee [108]

The specific heat of the metal is 2.4733 J/g°C.

Given the following data:

  • Initial temperature of water = 25.0°C
  • Final temperature of water = 29.0°C
  • Mass of water = 400.0 g
  • Mass of metal = 30.0 g
  • Temperature of metal = 203.0°C

We know that the specific heat capacity of water is 4.184 J/g°C.

To find the specific heat of the metal (J/g°C):

Heat lost by metal = Heat gained by water.

Q_{metal} = Q_{water}

Mathematically, heat capacity or quantity of heat is given by the formula;

Q = mc\theta

<u>Where:</u>

  • Q is the heat capacity or quantity of heat.
  • m is the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Substituting the values into the formula, we have:

30(203)c = 400(4.184)(29 \; -\; 20)\\\\6090c = 1673.6(9)\\\\6090c = 15062.4\\\\c = \frac{15062.4}{6090}

Specific heat capacity of metal, c = 2.4733 J/g°C

Therefore, the specific heat of the metal is 2.4733 J/g°C.

Read more: brainly.com/question/18691577

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