Answer:
The new volume is 7.27 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 7.0 L
The pressure = 765 mmHg = 765/760 atm = 1.00658 atm
The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737
The temperature remains constant
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the initial pressure in the balloon = 765 mmHg
⇒with V1 = the initial volume = 7.0L
⇒with P2 = the decreased pressure = 737 mmHg
⇒with V2 = the new volume = TO BE DETERMINED
765 mmHg * 7.0 L = 737 mmHG * V2
V2 = (765 mmHG * 7.0 L) / 737 mmHG
V2 = 7.27 L
The new volume is 7.27 L
Answer:
209.3 Joules require to raise the temperature from 10 °C to 15 °C.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m × c × ΔT
Given data:
mass of water = 10 g
initial temperature T1= 10 °C
final temperature T2= 15 °C
temperature change =ΔT= T2-T1 = 15°C - 10°C = 5 °C
Energy or joules added to increase the temperature Q = ?
Solution:
We know that specific heat of water is 4.186 J/g .°C
Q = m × c × ΔT
Q = 10 g × 4.186 J/g .°C × 5 °C
Q = 209.3 J
answer: D
Here is a list of the most common ways to speed up a chemical reaction
Increase the temperature (reactions that absorb energy)
Decrease the temperature (Reactions that release energy)
