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Leokris [45]
3 years ago
14

in isosceles triangle the length of a leg is 17 cm, the vase is 16 cm. find the length of the altitude to the base

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

15 cm

Step-by-step explanation:

The altitude is one leg of the right triangle formed by the altitude, half the base, and the triangle side. The Pythagorean theorem applies, so you have ...

... (17 cm)² = (altitude)² + (16 cm/2)²

... altitude = √(17² -8²) cm = √225 cm

... altitude = 15 cm

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3 0
3 years ago
Help me solve this please
shutvik [7]

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = \sqrt{(-28-3.5)^2+(-17.5-24.5)^2}

       = \sqrt{(-31.5)^2+42^2}

       = \sqrt{992.25+1764}

        = \sqrt{2756.25}

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mamaluj [8]
X + y + z = 2
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x + z = 2*(-5)
x + 5z = 6

-5x -5z = -10
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---------------------
-4x = -4 *(-1)
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x + y + z = 2
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S: {x, y, z} = {1, 0, 1}


8 0
3 years ago
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