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kumpel [21]
3 years ago
14

Please help with this answer

Chemistry
2 answers:
padilas [110]3 years ago
6 0

Answer:

D: wave B, wave B

Explanation:

As a frequency of a wave increases, the sound and the pitch also increases as well. Therefore, it causes the wave to be loud and dangerous.

Hope it helped!

Igoryamba3 years ago
4 0

Answer:

The answer is wave B, wave A

Explanation:

The closer the waves the higher the pitch. The higher the waves the louder it is.

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A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the
tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

0.143-0.1271=0.0159

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

0.0159/16.00=9.94*10^{-4}

There are 9.94*10^-4 moles of Oxygen.

6 0
1 year ago
Select the correct value for the indicated bond angle in each of the compounds.
Ira Lisetskai [31]

Answer:

Bond angle is defined as the angle between two or more bonds or bonded electron pairs in a compound.

Explanation:

a) O−O−O angle of O3 - <120°

b) F−B−F angle of BF3 - 120°

c) F−O−F angle of OF2 - <109.5

d) Cl−Be−Cl angle of BeCl2 - 180°

e) F−P−F angle of PF3 - 109.5°

f) Cl−Si−Cl angle of SiCl4 - 90°

7 0
3 years ago
Calculate the number of moles in 9.22 X 10^23 atom iron
sveta [45]
1.53 moles of Fe is your solution hope it helps!
7 0
2 years ago
The two factors that are most important in determining the density of air are:
Pie

Answer:

c. temperature and water vapor content.

Explanation:

The density of any substance is dependent of temperature, and in gases, the variations is greater than in any other substance, therefore, temperature is very important to calculate air density. Also, the concentration of water vapor in the air can vary depending  where is located, and that concentration will affect the density because it affects the average mass of air.

8 0
3 years ago
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An apprentice jeweler determines the density of a sample of pure gold to be 20.3 g/cm3. the accepted value is 19.3 g/cm3. what i
frosja888 [35]
We are tasked to find the percent error of the jeweler's density measurement through the formula:

%Error= Absolute Value(Experimental Value - Theoretical value) x 100%/ Theoretical Value

We are given by the problem,
Experimental Value=20.3 g/cm3
Theoretical Value= 19.3 g/cm3
By Substituting the details,
%Error= Absolute Value(20.3 g/cm3 - 19.3 g/cm3) x 100% / 19.3 g/cm3
%Error=Absolute Value (1)/19.3
%Error= 100/19.3
%Error= 5.18%

Therefore, 5.18% is the percent error committed by the jeweler<span />
3 0
4 years ago
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