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ankoles [38]
3 years ago
10

Which of the following is equal to 1W?A.1 JB.1 J/sC.1 J·sD.1 N·m

Physics
1 answer:
Ray Of Light [21]3 years ago
7 0
B. Extra text to get to 20 characters.
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Answer:

450m

Explanation:

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When analyzing the results of a scientific experiment, Kevin should base his conclusion on
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(a) Suppose a meter stick made of steel and one made of invar are the same length at 0°C. What is their difference in length at
dem82 [27]

Explanation:

Given that,

Initial temperature T_{i}=0^{\circ}C

Final temperature T_{f}=48.0^{\circ}C

Length = 34.0 m

We know that,

Coefficient of linear expansion of Invar is

\alpha=0.9\times10^{-6}/^{\circ}C

Coefficient of linear expansion of steel is

\alpha=12\times10^{-6}/^{\circ}C

We need to calculate the temperature difference is

\Delta T=T_{f}-T_{i}

\Delta T=48.0-0

\Delta T=48.0^{\circ}C

We need to calculate the change in length of Invar

Using formula of change in length

\Delta l=l\times\alpha\times\Delta t

Put the value into the formula

\Delta l=34\times0.9\times10^{-6}\times48.0

\Delta l=0.0014688=1.47\times10^{-3}\ m

\Delta l= 1.47\ mm

We need to calculate the change in length of steel

\Delta l'=34\times12\times10^{-6}\times48.0

\Delta l'=0.019584=19.59\times10^{-3}\ m

\Delta l'=19.59\ mm

Difference in length of two 34.0 m

Long surveyor's tapes is

\Delta L=\Delta l'-\Delta l

Put the value into the formula

\Delta L=19.59-1.47=18.12\ mm

The difference in length is 18.12 mm.

Hence, This is the required solution.

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