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3 years ago

How far did an object travel if they rode a bike at 15m/s for 5 seconds?

Physics

2 answers:

Nady [450]3 years ago

6 0

Answer:

A) 75m

Explanation:

distance = speed x time taken

Here given:

speed: 15 m/s

time: 5 second

So, distance covered:

15 x 5

75 m

s2008m [1.1K]3 years ago

6 0

Speed=15m/s
Time=5s

Distance

Speed×Time
15(5)
75m

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A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to

Verizon [17]

Answer:29.41 m/s

Explanation:

Given

Height of cliff 22.8 m

Height of river bank=2.4 m

width of river=60.0 m

Car can considered as projectile

Time travel to cover vertical distance=22.8-2.4=20.4 m

$h=ut+\frac{at^2}{2}$

$20.4=0+\frac{gt^2}{2}$

$t^2=4.163$

t=2.04 s

Range=60 m

Let u be the speed of car

ut=60

$u=\frac{60}{2.04}=29.41 m/s$

4 0

3 years ago

Kids are pelting a window with snowballs. On average, two snowballs of roughly 300-g mass hit the window each second, moving hor

hram777 [196]

Answer:

The average force exerted on the window due to two snowballs is 6 N

Explanation:

Given:

Mass of snowballs $m = 300 \times 10^{-3}$ Kg

Velocity of snowball $v = 10 \frac{m}{s}$

For finding the average force,

Force is equal to the change in momentum,

$F = \frac{dP}{dt}$

Here, final velocity is zero so we write,

$F = \frac{mv}{1}$

Where $dt = 1$ sec

$F = 300 \times 10^{-30} \times 10$

$F = 3$ N

Above value of force is due to one ball, but here given in question there are two ball,

$F = 3 \times 2$

$F = 6$ N

Therefore, the average force exerted on the window due to two snowballs is 6 N

5 0

4 years ago

A 0.1ohm resistor has power rating 5w. is the resistor safe when conducting a current of 10A.

astra-53 [7]

Answer:

1.5 Amp is rated for 5 W so it would not be possible

7 0

3 years ago

How fast must a 2.70-g ping-pong ball move in order to have the same kinetic energy as a 145-g baseball moving at 31.0 m/s

Helen [10]

Answer:

227 m/s

Explanation:

Kinetic energy formula:

$\displaystyle \text{KE} = \frac{1}{2} mv^2$

where m = mass of the object (kg)
and v = speed of the object (m/s)

Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.

First convert the mass to kilograms:

145-g → 0.145 kg

Plug known values into the KE formula.

$\displaystyle \text{KE} = \frac{1}{2} (.145)(31.0)^2$
$\displaystyle \text{KE} = 69.6725 \ \text{J}$

Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.

First convert the mass to kilograms:

2.70-g → 0.00270 kg

Plug known values into the KE formula.

$\displaystyle 69.6725 = \frac{1}{2} (.00270)v^2$
$\displaystyle \frac{2(69.6725)}{.00270} =v^2$
$57609.25926=v^2$
$v=227.1767137$

The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.

4 0

3 years ago

A cyclist starts from rest and coasts down a 4.0∘ hill. The mass of the cyclist plus bicycle is 85 kg. Ignore air resistance and

Angelina_Jolie [31]

A) change in ht after 180m = 180 * sin(4-deg.) = 12.56m

net work done by gravity on the cyclist = mass * gravity * height diff.

= 85 * 9.8 * 12.56

= 10470J

= 10.5kJ

B) Kinetic energy = 1/2 * mass * vel.^2 = work done by gravity = 10470J

vel.^2 = 10470 * 2 / 85 = 246.4

vel. = 15.7m/s

5 0

3 years ago