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rosijanka [135]
3 years ago
9

If the Fox for an object on an incline is 350N,

Physics
1 answer:
Alinara [238K]3 years ago
5 0
Pic? I need a pic thanks
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How big is the universe I get it only God knows because he created all of it meaning everything.That is real.
deff fn [24]

god is mighty not only did he create the universe but also everything in it

but here's the answer 93 billion light years

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3 years ago
Newton's 2nf law of motion States that
lapo4ka [179]

Answer:

B (force = mass X acceleration)

Explanation:

The acceleration of an object depends on the mass of the object and the amount of force applied. His second law defines a force to be equal to change in momentum (mass times velocity) per change in time.

Formula: F = m x a

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2 years ago
two charges + 2.6 uc and -5.4uc experience an attractive force of 6.5mN. What is the separation between the charges?
djyliett [7]

Answer:

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Explanation:

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7 0
3 years ago
A box weighing 52.4 N is sliding on a rough horizontal floor with a constant friction force of magnitude LaTeX: ff. The box's in
german

Answer:

The magnitude of the friction force exerted on the box is 2.614 newtons.

Explanation:

Since the box is sliding on a rough horizontal floor, then it is decelerated solely by friction force due to the contact of the box with floor. The free body diagram of the box is presented herein as attachment. The equation of equilbrium for the box is:

\Sigma F = -f = m\cdot a (Eq. 1)

Where:

f - Kinetic friction force, measured in newtons.

m - Mass of the box, measured in kilograms.

a - Acceleration experimented by the box, measured in meters per square second.

By applying definitions of weight (W = m\cdot g) and uniform accelerated motion (v = v_{o}+a\cdot t), we expand the previous expression:

-f = \left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)

And the magnitude of the friction force exerted on the box is calculated by this formula:

f = -\left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right) (Eq. 1b)

Where:

W - Weight, measured in newtons.

g - Gravitational acceleration, measured in meters per square second.

v_{o} - Initial speed, measured in meters per second.

v - Final speed, measured in meters per second.

t - Time, measured in seconds.

If we know that W = 52.4\,N, g = 9.807\,\frac{m}{s^{2}}, v_{o} = 1.37\,\frac{m}{s}, v = 0\,\frac{m}{s} and t = 2.8\,s, the magnitud of the kinetic friction force exerted on the box is:

f = -\left(\frac{52.4\,N}{9.807\,\frac{m}{s^{2}} } \right)\cdot \left(\frac{0\,\frac{m}{s}-1.37\,\frac{m}{s}  }{2.8\,s} \right)

f = 2.614\,N

The magnitude of the friction force exerted on the box is 2.614 newtons.

5 0
3 years ago
An atom of element X has one more shell of electrons than an atom of beryllium, but it has one less valence electron than beryll
3241004551 [841]
The correct answer is Sodium
8 0
3 years ago
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