Answer:
Explanation:
For fundamental frequency in a vibrating string , the formula is
n = 1 / 2L x √ ( T /m₁ )
n is frequency , L is length , T is tension and m₁ is mass per unit length .
For first string ,
293 = 1 / 2L x √ ( 49 N /m₁ )
For second string , let mass per unit length be m₂ .
196 = 1 / 2L x √ ( 49 N /m₂ ) ------ ( 1 )
To bring its frequency back to previous one let tension be T
293 = 1 / 2L x √ ( T /m₂ ) ------- ( 2 )
Dividing
293 / 196 = √ ( T /49 )
1.4948 = √ ( T /49 )
2.2344 = T /49
T = 109.48 N .
To solve this problem it is necessary to apply the equation related to the Gravitational Force, the equation describes that

Where,
G = Gravitational Universal Constant
M = Mass of Earth (or Bigger star)
m = Mass of Object (or smallest star)
r = Radius
From the statement we know that once the impact is made, the golf ball is subjected to the forces that are exerted in nature. Since the air resistance, which would represent the drag force, is ignored. Only the forces related to gravity remain.
The gravitational force carries 'pushes' or 'attracts' the body towards the earth, while the speed decreases as it reaches its maximum height.
When the ball has reached its maximum height only the force of gravity begins to act on it, generating the attraction to the earth in parabolic motion.
Therefore the correct answer is B.
The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.
<h3>What is the speed of wave?</h3>
Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

Here, (f) is the frequency and (λ) is the wavelength.
The frequency is inverse of time. Thus, the value of frequency in time t is,

The speed of the wave is 0.5 m/s. Put the values in the formula,

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.
Learn more about the speed of wave here;
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<span>stuntman's vertical velocity is
vy= 6 sin 15=1.55m/s.
Height that he goes up is,
vertical kinetic energy = mgh
1/2 v² = gh, h=v²/(2g)=0.12 m.
time wanted to go up= vy/9.8=0.16s, Time to fall through a height
0.12+2.9=3.02m is
t=sqrt(3.02*2/9.8)=0.78 s
Total time needed to go up and down is 0.78+0.16=0.94 s.
to calculate the horizontal range,
Horizontal velocity = 6 cos 15=5.8 m/s.
Distance which he can cover is
5.8*0.94=5.44 m.
If the distance between the two building is less than 5.44 m then he will be safe and he can jump that distance.</span>