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3 years ago

What is the chemical formula of trisilicon tetranitride? A. Si3N4 B. Si4N3 C. Si3N6 D. Si6N3 E. Si4N6 Reset Next

Chemistry

2 answers:

kherson [118]3 years ago

5 0

The answer is Si3N4 (A).

vekshin13 years ago

4 0

Answer : The correct option is, (A) $Si_3N_4$

Explanation :

Trisilicon tetranitride is a covalent compound because sharing of electrons takes place between silicon and nitrogen. Both the elements are non-metals and hence, will form a covalent bond.

The formula of covalent compound is given by :

The less electronegative element is written first.
The more electronegative element is written next.
If atoms of an element is greater than 1 that means their prefixes are written in the respective element's subscript.

As per given name of compound, the less electronegative element is 'Si' and more electronegative element is 'N'.

So, the chemical formula of trisilicon tetranitride is, $Si_3N_4$

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Read 2 more answers

Why do we use 51.0mL of NaOH but only 50.0mL of HCl?

bixtya [17]

Answer

Na OH reacts with H Cl and forms Na Cl and H₂O

NaOH + HCl → NaCl + H₂O

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3 years ago

A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi

Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

Step 1: Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

Step 2: Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0

3 years ago

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3 years ago