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docker41 [41]
3 years ago
15

What is the chemical formula of trisilicon tetranitride? A. Si3N4 B. Si4N3 C. Si3N6 D. Si6N3 E. Si4N6 Reset Next

Chemistry
2 answers:
kherson [118]3 years ago
5 0

The answer is Si3N4 (A).

vekshin13 years ago
4 0

Answer : The correct option is, (A) Si_3N_4

Explanation :

Trisilicon tetranitride is a covalent compound because sharing of electrons takes place between silicon and nitrogen. Both the elements are non-metals and hence, will form a covalent bond.

The formula of covalent compound is given by :

  • The less electronegative element is written first.
  • The more electronegative element is written next.
  • If atoms of an element is greater than 1 that means their prefixes are written in the respective element's subscript.

As per given name of compound, the less electronegative element is 'Si' and more electronegative element is 'N'.

So, the chemical formula of trisilicon tetranitride is, Si_3N_4

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On the basis of the Ksp values below, what is the order of the solubility from least soluble to most soluble for these compounds
Viktor [21]

Answer:

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

Explanation:

The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:

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It follows then  that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:

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Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹²  with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of  the ratio of ions 2:1 in Ag2CO3,  so the answer is not obvious. But since we know that

Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋

Ksp Ag2CO3  = 2s x s = 2 s² =  8.0 x 10-12

s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶

And for AgCl

AgCl  ⇄ Ag⁺ + Cl⁻

Ksp = s² = 1.8 x 10⁻¹⁰  ∴ s = √ 1.8 x 10⁻¹⁰   = 1.3 x 10⁻⁵

Therefore, AgCl is more soluble than Ag₂CO₃

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

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