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3 years ago

in the reaction mgcl2 + 2koh mg(oh)2 + 2kcl, if 3 moles mgcl2 are added to 4 moles koh what determines how much mg(oh)2 is made

2 answers:

6 0

Every mole of MgCl2 reacts with 2 moles of KOH, therefore the 4 moles of KOH will only react with 2 moles of MgCl2, making it the limiting reagent and therefore KOH determines how much Mg(OH)2 is produced.

yanalaym [24]3 years ago

3 0

The amount of KOH --apex

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3 years ago

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3 years ago

Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.

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The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element % Atomic mass Relative no. of atoms Simplest whole ratio

C 40.6 12 $\frac{40.6}{12}$ = 3.3 $\frac{3.3}{3.3} = 1$

H 5.1 1 $\frac{5.1}{1}$ = 5.1 $\frac{5.1}{3.1} = 2$

O 54.2 16 $\frac{54.2}{16}$ = 3.3 $\frac{3.3}{3.3} = 1$

The Empirical formula of compound is C₁H₂O₁ or CH₂O

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

$n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}$

$= \frac{118.084}{30}$

= 4

Molecular formula = n × Empirical formula

= 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

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