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2 years ago

in the reaction mgcl2 + 2koh mg(oh)2 + 2kcl, if 3 moles mgcl2 are added to 4 moles koh what determines how much mg(oh)2 is made

2 answers:

6 0

Every mole of MgCl2 reacts with 2 moles of KOH, therefore the 4 moles of KOH will only react with 2 moles of MgCl2, making it the limiting reagent and therefore KOH determines how much Mg(OH)2 is produced.

yanalaym [24]2 years ago

3 0

The amount of KOH --apex

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20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

8 0

3 years ago

How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water

erik [133]

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

we need to convert g - mg

500g = 500 x 10⁻³mg = 0.5mg

Concentration in parts per million = $\frac{mass in mg}{Volume in liters}$

Concentration in parts per million = $\frac{0.5}{500000}$ = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

7 0

3 years ago

How many grams are in 5 mols of KOH

elena55 [62]

Answer:

0.08911760029829444

Explanation:

hop that this what you wanted

8 0

2 years ago

What volume of a 5.00M solution of hydrochloric acid contains 8.00mol of HCl?

rjkz [21]

Answer:

520ML and apparently I need to put more in this answer

Explanation:

brainly.com

7 0

3 years ago

What is the difference between creep and a landslide?

Oksanka [162]

Creep is somthing you might call somone following you. Example, "he was slowly creeping up the stairs behind me". A land slide normally moves faster then that.

4 0

3 years ago