Answer: 15.66 °
Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:
F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.
From this expression and using the given values we obtain the following:
F/(q*v*B) = sin α
3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27
then α =15.66°
Answer:
1st: Theatre History
4th Quarter
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Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Explanation:
1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps
